我有自定义ContentControl
public class DataControl : ContentControl
{
public List<DataItem> Options
{
get { return (List<DataItem>)GetValue(OptionsProperty); }
set { SetValue(OptionsProperty, value); }
}
public static readonly DependencyProperty OptionsProperty =
DependencyProperty.Register("Options", typeof(List<DataItem>), typeof(DataControl));
public DataControl()
{
Options = new List<DataItem>();
}
public string Label
{
get { return (string)GetValue(LabelProperty); }
set { SetValue(LabelProperty, value); }
}
// Using a DependencyProperty as the backing store for Label. This enables animation, styling, binding, etc...
public static readonly DependencyProperty LabelProperty =
DependencyProperty.Register("Label", typeof(string), typeof(DataControl));
}
public class DataItem
{
public DataItem(string key, string value)
{
Key = key;
Value = value;
}
public string Key { get; set; }
public string Value { get; set; }
}
其模板由以下样式应用:
<Style TargetType="{x:Type local:DataControl}" x:Key="DefaultStyle">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type local:DataControl}">
<StackPanel>
<ListBox ItemsSource="{TemplateBinding Options}" >
<ListBox.ItemTemplate>
<DataTemplate>
<Label Content="{Binding Key}" />
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
<Label Content="{TemplateBinding Label}" />
</StackPanel>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
如果我使用XamlWriter保存此样式然后再次将其读回,则ItemsSource绑定将丢失,但Label上的Content绑定不会丢失。
Style style = Application.Current.TryFindResource("DefaultStyle") as Style;
string s = XamlWriter.Save(style);
Style secondStyle = XamlReader.Parse(s) as Style;
有没有办法确保ItemsSource绑定被正确序列化或者将其重新添加回来?
当尝试从另一个项目的ResourceDictionary获取Style时也会发生这种情况,例如
ResourceDictionary styles = new ResourceDictionary();
styles.Source = new Uri(String.Format("pack://application:,,,/StyleCopyTest;component/Styles/{0}Styles.xaml", type));
return styles;
答案 0 :(得分:2)
在WPF源代码中,ItemsSource定义为
[Bindable(true), CustomCategory("Content"), DesignerSerializationVisibility(DesignerSerializationVisibility.Hidden)]
public IEnumerable ItemsSource { get; set; }
所以这不能被XamlWriter序列化。
因此,您必须编写自己的序列化程序或使用提及here
的方法答案 1 :(得分:0)
我发现这个类here in code project可以帮助您序列化ItemsControl属性绑定:
using System;
using System.Linq;
using System.ComponentModel;
namespace GUIKonfigurator
{
using System.Windows.Controls;
public class ItemsControlTypeDescriptionProvider:TypeDescriptionProvider
{
private static readonly TypeDescriptionProvider defaultTypeProvider = TypeDescriptor.GetProvider(typeof(ItemsControl));
public ItemsControlTypeDescriptionProvider(): base(defaultTypeProvider)
{
}
public static void Register()
{
TypeDescriptor.AddProvider(new ItemsControlTypeDescriptionProvider(), typeof(ItemsControl));
}
public override ICustomTypeDescriptor GetTypeDescriptor(Type objectType,object instance)
{
ICustomTypeDescriptor defaultDescriptor = base.GetTypeDescriptor(objectType, instance);
return instance == null ? defaultDescriptor: new ItemsControlCustomTypeDescriptor(defaultDescriptor);
}
}
internal class ItemsControlCustomTypeDescriptor: CustomTypeDescriptor
{
public ItemsControlCustomTypeDescriptor(ICustomTypeDescriptor parent): base(parent)
{
}
public override PropertyDescriptorCollection GetProperties()
{
PropertyDescriptorCollection pdc = new PropertyDescriptorCollection(base.GetProperties().Cast<PropertyDescriptor>().ToArray());
return ConvertPropertys(pdc);
}
public override PropertyDescriptorCollection GetProperties(Attribute[] attributes)
{
PropertyDescriptorCollection pdc = new PropertyDescriptorCollection(base.GetProperties(attributes).Cast<PropertyDescriptor>().ToArray());
return ConvertPropertys(pdc);
}
private PropertyDescriptorCollection ConvertPropertys(PropertyDescriptorCollection pdc)
{
PropertyDescriptor pd = pdc.Find("ItemsSource", false);
if (pd != null)
{
PropertyDescriptor pdNew = TypeDescriptor.CreateProperty(typeof(ItemsControl), pd, new Attribute[]
{
new DesignerSerializationVisibilityAttribute(DesignerSerializationVisibility.Visible),
new DefaultValueAttribute("")
});
pdc.Add(pdNew);
pdc.Remove(pd);
}
return pdc;
}
}
}
注册BindingConvertor后,您只需要这样注册:
EditorHelper.Register<BindingExpression, BindingConvertor>();
ItemsControlTypeDescriptionProvider.Register();
这是我做的快速测试,创建了一个ComboBox并将其序列化:
ComboBox cb = new ComboBox();
cb.Width = 100;
cb.Height = 20;
Binding b = new Binding("Model.Activity");
b.Source = this.DataContext;
cb.SetBinding(ComboBox.ItemsSourceProperty, b);
string xaml = _Serializer.SerializeControlToXaml(cb);
这里产生的Xaml包括ItemsSource绑定:
<ComboBox Width="100" Height="20" ItemsSource="{Binding Path=Model.Activity}" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" />
希望这有帮助,我仍然需要花一些时间来理解它,但到目前为止似乎正在起作用......