Question

我是Play的新手，在部署时遇到问题在prod模式下应用。我在内存中使用db开始.... 播放版本为1.2.4 我用实体制作了一个简单的应用程序

@Entity
public class TestModel extends Model {


   public String name;

}

和conf as

 application.mode=prod
 db=mem
%test.application.mode=prod
%test.db.url=jdbc:h2:mem:play;MODE=MYSQL;LOCK_MODE=0
%test.jpa.ddl=create
 %test.mail.smtp=mock

控制器中的

仅用于测试我正在做的是

     public static void listBars() {

           TestModel bar = new TestModel();

       bar.name = "a new bar";
       bar.save();
       TestModel bar2 = new TestModel();
       bar2.name = "a new bar2";
       bar2.save();



   renderJSON(TestModel.findAll());
}

真的很感激，如果我能得到一些帮助..代码正在开发模式..

异常跟踪是

       va:116)
       at org.hibernate.id.IdentityGenerator$GetGeneratedKeysDelegate.prepare(I
entityGenerator.java:90)
       at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(Abstr
ctReturningDelegate.java:54)
       ... 24 more
9:57:31,396 WARN  ~ SQL Error: 42102, SQLState: 42S02
9:57:31,397 ERROR ~ Table "TESTMODEL" not found; SQL statement:
nsert into TestModel (id, name) values (null, ?) [42102-149]
9:57:31,404 ERROR ~

69772kodd
nternal Server Error (500) for request POST /bars.json

xecution exception (In /app/controllers/Application.java around line 30)
ersistenceException occured : org.hibernate.exception.SQLGrammarException: coul
 not insert: [models.TestModel]

lay.exceptions.JavaExecutionException: org.hibernate.exception.SQLGrammarExcept
on: could not insert: [models.TestModel]
       at play.mvc.ActionInvoker.invoke(ActionInvoker.java:231)
       at Invocation.HTTP Request(Play!)
aused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGr
mmarException: could not insert: [models.TestModel]
       at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityMan
gerImpl.java:1214)
       at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityMan
gerImpl.java:1147)
       at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityMan

Answer 1

你需要使用这样的东西来自动生成你的表：

jpa.ddl =创建

每次生产时都不要重新生成表格，以防止丢失数据。

查看此页面：http://www.playframework.org/documentation/1.2.4/production 部分：禁用JPA自动架构更新

在prod模式下播放框架工作表未找到错误

1 个答案: