我有选择,iside选择有2列。此列必须从相同的选择中填充,但我不希望使用select两次。是否可以使用选择1次,然后从第一次设置第二列值? 例如:
insert into @temptable from
select
a = (select aa from table1 where quantity > 5)
b = (select aa from table1 where quantity > 5)
我需要:
insert into @temptable from
select
a = (select aa from table1 where quantity > 5)
b = {value from a}
更新。我写了一个不好的例子,我需要设置Balance的BalancePrediction1和BalancePrediction2值
INSERT @tmpBalances
SELECT PA.ContractId AS 'ContractId',
Con.Name AS 'ContractName',
Bal.PortfolioAccountId AS 'PortfolioAccountId',
PA.Name AS 'PortfolioAccountName',
RA.GeneralId AS 'RegisterAccountGeneralId',
Bal.BalanceTypeId AS 'BalanceTypeId',
Bt.Name AS 'BalanceTypeName',
Bt.Type AS 'BalanceTypeType',
Bal.BalanceTimeType AS 'BalanceTimeType',
Bal.InstrumentId AS 'InstrumentId',
Ins.Name AS 'InstrumentName',
Ins.GeneralId AS 'InstrumentGeneralId',
(Bal.Balance -
(
SELECT COALESCE(SUM(Mov.Amount), 0)
FROM trd.Movements AS Mov
WHERE
Bal.InstrumentId = Mov.InstrumentId AND
Bal.PortfolioAccountId = Mov.PortfolioAccountId AND
Bal.BalanceTypeId = Mov.BalanceTypeId AND
Bal.BalanceTimeType = Mov.BalanceTimeType AND
DateDiff(DAY, @Date, Mov.Date) > 0 AND
-- Currency může být null a NULL = NULL nejde
COALESCE(Bal.CurrencyId, -1) = COALESCE(Mov.CurrencyId, -1)
)
) as Balance,
Balance AS 'BalancePrediction1',
Balance AS 'BalancePrediction2',
Bal.CurrencyId AS 'CurrencyId',
Ccy.Code AS 'CurrencyCode',
PA.PositionServiceType 'PositionServiceType',
Ccy.Name 'CurrencyName',
S.Nominal AS 'Nominal',
S.NominalCurrencyId AS 'NominalCurrencyId',
trd.GetCurrencyCode(S.NominalCurrencyId) AS 'NominalCurrencyCode'
FROM trd.Balances AS Bal
JOIN trd.PortfolioAccounts AS PA ON PA.Id = Bal.PortfolioAccountId
JOIN trd.Contracts AS Con ON Con.Id = PA.ContractId
JOIN trd.RegisterAccounts AS RA ON RA.Id = PA.RegisterAccountId
JOIN trd.BalanceTypes AS Bt ON Bt.Id = Bal.BalanceTypeId
JOIN trd.Instruments AS Ins ON Ins.Id = Bal.InstrumentId
LEFT OUTER JOIN trd.Currencies AS Ccy ON Ccy.Id = Bal.CurrencyId
LEFT JOIN trd.SecuritiesView S ON s.Id = Ins.Id AND DateDiff(d, S.ValidFrom, @Date) >= 0 AND (S.ValidTo IS NULL OR DateDiff(d, S.ValidTo, @Date) < 0)
AND S.InstrumentInstrumentTypePriceUnit = 1
答案 0 :(得分:3)
您可以在插入后对表变量进行更新。
update @tmpBalances
set BalancePrediction1 = Balance,
BalancePrediction2 = Balance
或者您可以使用cross apply
来计算总和。
INSERT @tmpBalances
SELECT PA.ContractId AS 'ContractId',
Con.Name AS 'ContractName',
Bal.PortfolioAccountId AS 'PortfolioAccountId',
PA.Name AS 'PortfolioAccountName',
RA.GeneralId AS 'RegisterAccountGeneralId',
Bal.BalanceTypeId AS 'BalanceTypeId',
Bt.Name AS 'BalanceTypeName',
Bt.Type AS 'BalanceTypeType',
Bal.BalanceTimeType AS 'BalanceTimeType',
Bal.InstrumentId AS 'InstrumentId',
Ins.Name AS 'InstrumentName',
Ins.GeneralId AS 'InstrumentGeneralId',
(Bal.Balance - Mov.SumAmount) AS Balance,
(Bal.Balance - Mov.SumAmount) AS 'BalancePrediction1',
(Bal.Balance - Mov.SumAmount) AS 'BalancePrediction2',
Bal.CurrencyId AS 'CurrencyId',
Ccy.Code AS 'CurrencyCode',
PA.PositionServiceType 'PositionServiceType',
Ccy.Name 'CurrencyName',
S.Nominal AS 'Nominal',
S.NominalCurrencyId AS 'NominalCurrencyId',
trd.GetCurrencyCode(S.NominalCurrencyId) AS 'NominalCurrencyCode'
FROM trd.Balances AS Bal
JOIN trd.PortfolioAccounts AS PA ON PA.Id = Bal.PortfolioAccountId
JOIN trd.Contracts AS Con ON Con.Id = PA.ContractId
JOIN trd.RegisterAccounts AS RA ON RA.Id = PA.RegisterAccountId
JOIN trd.BalanceTypes AS Bt ON Bt.Id = Bal.BalanceTypeId
JOIN trd.Instruments AS Ins ON Ins.Id = Bal.InstrumentId
LEFT OUTER JOIN trd.Currencies AS Ccy ON Ccy.Id = Bal.CurrencyId
LEFT JOIN trd.SecuritiesView S ON s.Id = Ins.Id AND DateDiff(d, S.ValidFrom, @Date) >= 0 AND (S.ValidTo IS NULL OR DateDiff(d, S.ValidTo, @Date) < 0)
AND S.InstrumentInstrumentTypePriceUnit = 1
CROSS APPLY (SELECT COALESCE(SUM(Mov.Amount), 0)
FROM trd.Movements AS Mov
WHERE
Bal.InstrumentId = Mov.InstrumentId AND
Bal.PortfolioAccountId = Mov.PortfolioAccountId AND
Bal.BalanceTypeId = Mov.BalanceTypeId AND
Bal.BalanceTimeType = Mov.BalanceTimeType AND
DateDiff(DAY, @Date, Mov.Date) > 0 AND
-- Currency může být null a NULL = NULL nejde
COALESCE(Bal.CurrencyId, -1) = COALESCE(Mov.CurrencyId, -1)
) Mov(SumAmount)
答案 1 :(得分:1)
SELECT aa AS a, aa AS b
FROM table1
WHERE quantity > 5
答案 2 :(得分:0)
单向;
;with T (value) as (
select aa from table1 where quantity > 5
)
insert into @temptable
select value, value from T