我有一个类似于以下
的数据表public static DataTable SetColumnHeaders(DataTable KeyDataTable)
{
KeyDataTable.Columns.Add("First_Name", typeof(string));
KeyDataTable.Columns.Add("Last_Name", typeof(string));
KeyDataTable.Columns.Add("Address1", typeof(string));
KeyDataTable.Columns.Add("Address2", typeof(bool));
KeyDataTable.Columns.Add("City", typeof(string));
KeyDataTable.Columns.Add("State", typeof(bool));
KeyDataTable.Columns.Add("Zip", typeof(string));
KeyDataTable.Columns.Add("Zip4", typeof(bool));
KeyDataTable.Columns.Add("Match_File", typeof(bool));
return KeyDataTable;
}
我的目标是从xml读取信息并将该特定数据存储到我的数据表中。我为每个“Quote”都有一个单独的xml文件，所以我将向数据表添加一个新行。我关心的xml部分如下：
'- <ACORD>
- <SignonRq>
- <SignonPswd>
- <CustId>
<SPName>com.agencyport</SPName>
</CustId>
- <CustPswd>
<EncryptionTypeCd>NONE</EncryptionTypeCd>
<Pswd>default</Pswd>
</CustPswd>
</SignonPswd>
<ClientDt>2006-04-04T15:44:00</ClientDt>
<CustLangPref>en-US</CustLangPref>
- <ClientApp>
<Org>Applied Systems</Org>
<Name>WinTam</Name>
<Version>7.1.0</Version>
</ClientApp>
</SignonRq>
- <InsuranceSvcRq>
<RqUID>81913CB5-3EAB-F158-EE24-5910F9BE9C26</RqUID>
- <PersAutoPolicyQuoteInqRq>
<RqUID>7B010E52-44F2-487A-521B-9D1E3500C23D</RqUID>
- <Producer id="AB4E95FF02FA91FAA4D7A2D96B59D8866A">
- <ProducerInfo id="AF04551B40F1439BCCC77CA3A21165FFAA">
<ContractNumber id="AD2178F32385016684F33F848830CAA18A">AP</ContractNumber>
</ProducerInfo>
</Producer>
<InsuredOrPrincipal id="A498E0A503206279EE434988B68472974A">
<GeneralPartyInfo id="A4F0BBE53B311050FD0552BB41090A523A">
<NameInfo id="AFBDE1032EEEA0821374C7C9428B0B44CA">
<PersonName id="A883A5BFD8FA8E71F52780B1E678AD64AA">
<Surname id="A40A625346687D257582BF6499710839BA">TEST</Surname>
<GivenName id="A021FD886DAAF628327F542786B6CD9B5A">TEST</GivenName>
<OtherGivenName id="A06DB1E21AF9BD37420B5C39E6562C78AA">TEST</OtherGivenName>
</PersonName>
<TaxIdentity id="ABC2680C3B21A161E54BCDBA78DFCCE77A">
<TaxIdTypeCd id="A050BE41EE9F2B1C713E934B1D6D2B31BA">SSN</TaxIdTypeCd>
</TaxIdentity>
</NameInfo>
<Addr id="A0C5DF11BD2CF70669AE368F685DAD141A">
<AddrTypeCd id="A82658A7F5CEB14239A4023874F594FC9A">MailingAddress</AddrTypeCd>
<Addr1 id="A0DC5C008818A7559527AD40AB1E0D8E0A">100 MAIN ST</Addr1>
<City id="A7DBC851540752437C649745A63508198A">Howell</City>
<StateProvCd id="ACDF462092E91668AD7996C662ACC1622A">MI</StateProvCd>
<PostalCode id="A45C6341382A3314D1EC79FEF20FE9D82A">48843</PostalCode>
<CountryCd id="AD69C7B00BB7F210588E016FF281675F6A">Livingston</CountryCd>
</Addr>
<Communications id="AFC53B2B003342664BE4635C38C7C6C45A">
<PhoneInfo id="AE5497FDB30717F033E8DFA47B3A36142A">
<PhoneTypeCd id="AF8662F35A8F1FD3DD993CECB53EB2FCAA">Phone</PhoneTypeCd>
<CommunicationUseCd id="ADA98E4A9B820C002189B1124F071D462A">Home</CommunicationUseCd>
<PhoneNumber id="A7F0F2A55F636FB6DCED2F6815271B352A">313-272-6576</PhoneNumber>
</PhoneInfo>
</Communications>
</GeneralPartyInfo>
<InsuredOrPrincipalInfo id="A09004254D9A7BE38EA45B20CCD6A0EC2A">
<InsuredOrPrincipalRoleCd id="A2B16D7C6D9CE94DB83DDC6C69BE52BDBA">Insured</InsuredOrPrincipalRoleCd>
<PersonInfo id="AE7CB4EE90C6BEBB1C79DF10415B3B8E5A">
<MiscParty id="A3AC37CD29B32FA46D0204601CE86F0C0A">
<MiscPartyInfo id="A5A9326BB8C3E68900D23F62420A06362A">
<MiscPartyRoleCd id="A92E022991F988677D6EF8434207DDEBBA">Employer</MiscPartyRoleCd>
</MiscPartyInfo>
</MiscParty>
</PersonInfo>
</InsuredOrPrincipalInfo>
</InsuredOrPrincipal>
到目前为止我想出的是：
public static void ExportAutoToText()
{
DirectoryInfo AutoDir = new DirectoryInfo(FilePrep.AutoDirectory);
DataTable AutoDataTable = new DataTable();
AutoDataTable = SetColumnHeaders(AutoDataTable); // set column headers
foreach (FileInfo File in AutoDir.GetFiles())
{
DataRow fileRow = AutoDataTable.NewRow();
XDocument xmlDoc = XDocument.Load(AutoDir + File.Name);
//decide if i want to keep the file
IEnumerable<XElement> personinfo =
from per in xmlDoc.Root.Descendants("InsuredOrPrincipal")
where (string)per.Element("InsuredOrPrincipalInfo")
.Element("InsuredOrPrincipalRoleCd") == ("Insured")
select per;
// I then want to update the information in my datatable
//fileRow["First_Name"] = xVal.Element("GeneralPartyInfo")
// .Element("NameInfo")
// .Element("PersonName")
// .Element("GivenName");
//fileRow["Last_Name"] = xVal.Element("GeneralPartyInfo")
// .Element("NameInfo")
// .Element("PersonName")
// .Element("Surname");
}
}
此方法位于Class内部，因此您可以假设获取文件，一切正常。我只需要知道从xml文件访问数据并将其存储在我的数据表中的最有效方法。我尝试循环数据如下：
foreach (var Xval in personinfo)
{
//get the element info
}
我对xml知之甚少，不知道如何访问它。再次感谢，如果您需要更多信息，请告诉我。 **
答案 0 :(得分：2)
我更喜欢为每个节点级别创建对象。它更容易调试和测试。
使用此xml library。
您可以为每个部分创建类，例如：
public class InsuredOrPrincipal
{
XElement self;
public InsuredOrPrincipal(XElement self) { this.self = self; }
public GeneralPartyInfo GeneralPartyInfo { get { return _GeneralPartyInfo ?? (_GeneralPartyInfo = new GeneralPartyInfo(self.GetElement("GeneralPartyInfo"))); } }
GeneralPartyInfo _GeneralPartyInfo;
public InsuredOrPrincipalInfo InsuredOrPrincipalInfo
{ get { return _InsuredOrPrincipalInfo ?? (_InsuredOrPrincipalInfo = new InsuredOrPrincipalInfo(self.GetElement("InsuredOrPrincipalInfo"))); } }
InsuredOrPrincipalInfo _InsuredOrPrincipalInfo;
}
public class GeneralPartyInfo
{
XElement self;
public GeneralPartyInfo(XElement self) { this.self = self; }
public NameInfo NameInfo { get { return _NameInfo ?? (_NameInfo = new NameInfo(self.GetElement("NameInfo"))); } }
NameInfo _NameInfo;
}
public class InsuredOrPrincipalInfo
{
XElement self;
public InsuredOrPrincipalInfo(XElement self) { this.self = self; }
public string InsuredOrPrincipalRoleCd
{
get { return self.Get("InsuredOrPrincipalRoleCd", string.Empty); }
}
}
public class NameInfo
{
XElement self;
public NameInfo(XElement self) { this.self = self; }
public PersonName PersonName { get { return _PersonName ?? (_PersonName = new PersonName(self.GetElement("PersonName"))); } }
PersonName _PersonName;
}
public class PersonName
{
XElement self;
public PersonName(XElement self) { this.self = self; }
public string Surname
{
get { return self.Get("Surname", string.Empty); }
set { self.Set("Surname", value, false); }
}
}
您可以这样使用它：
foreach (FileInfo File in AutoDir.GetFiles())
{
DataRow fileRow = AutoDataTable.NewRow();
XDocument xmlDoc = XDocument.Load(AutoDir + File.Name);
InsuredOrPrincipal[] insured = xmlDoc.Root
.Descendants("InsuredOrPrincipal")
.Select(x => new InsuredOrPrincipal(x))
.Where(ip => ip.InsuredOrPrincipalInfo.InsuredOrPrincipalRoleCd == "Insured")
.ToArray();
foreach(var person in insured)
{
string surname = person.GeneralPartyInfo.NameInfo.PersonName.Surname;
}
}
根据您的需要，您可以根据需要扩展或缩小每个班级的班级和信息数量，但这是我的方式，因为它对我来说更有意义。
使用此代码进行测试：
XElement test = new XElement("test");
var ip = new InsuredOrPrincipal(test);
ip.GeneralPartyInfo.NameInfo.PersonName.Surname = "Surname";
test.Save(Path.Combine(Application.StartupPath, "insuredOrPrincipal.xml"));
这给了我预期的输出：
<?xml version="1.0" encoding="utf-8"?>
<InsuredOrPrincipal>
<GeneralPartyInfo>
<NameInfo>
<PersonName>
<Surname>Surname</Surname>
</PersonName>
</NameInfo>
</GeneralPartyInfo>
</InsuredOrPrincipal>
答案 1 :(得分：0)
您可以将“isInsured”支票和您选择的人员加入一个查询中;
var query = from p in xmlDoc.Elements()
where ((string)p.Element("InsuredOrPrincipalInfo")
.Element("InsuredOrPrincipalRoleCd")) == "Insured"
select new
{
Firstname = (string)p.Element("GeneralPartyInfo")
.Element("NameInfo")
.Element("PersonName")
.Element("GivenName"),
LastName = (string)p.Element("GeneralPartyInfo")
.Element("NameInfo")
.Element("PersonName")
.Element("Surname"),
};
var person = query.FirstOrDefault();
if (person != null)
{
var fileRow = AutoDataTable.NewRow();
fileRow["First_Name"] = person.Firstname;
fileRow["Last_name"] = person.LastName;
}
在处理意外格式的XML方面，这不是非常强大，但它应该是一个很好的起点。只需用其余元素填写匿名对象初始化，然后转换为所需的类型。
答案 2 :(得分：0)
这是我到目前为止所拥有的。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;
using System.IO;
using System.Data;
namespace xmlCustomReformat
{
class importXml
{
public DataTable _ComboDataTable;
public void ExportAutoToText()
{
DirectoryInfo AutoDir = new DirectoryInfo(FilePrep.AutoDirectory);
CreateDataTable(); // set column headers
foreach (FileInfo File in AutoDir.GetFiles())
{
DataRow fileRow = _ComboDataTable.NewRow();
XDocument xmlDoc = XDocument.Load(AutoDir + File.Name);
InsuredOrPrincipal[] insured = xmlDoc.Root
.Descendants("InsuredOrPrincipal")
.Select(x => new InsuredOrPrincipal(x))
.Where(ip => ip.InsuredOrPrincipalInfo.InsuredOrPrincipalRoleCd == "Insured")
.ToArray();
foreach (var person in insured)
{
fileRow["First_Name"] = person.GeneralPartyInfo.NameInfo.PersonName.GivenName;
fileRow["Last_name"] = person.GeneralPartyInfo.NameInfo.PersonName.Surname;
fileRow["Address1"] = person.GeneralPartyInfo.Addr.Address1;
fileRow["City"] = person.GeneralPartyInfo.Addr.City;
fileRow["State"] = person.GeneralPartyInfo.Addr.State;
fileRow["Zip"] = person.GeneralPartyInfo.Addr.Zip;
fileRow["Address2"] = " ";
fileRow["Zip4"] = " ";
fileRow["Match_File"] = File.Name.ToString();
_ComboDataTable.Rows.Add(fileRow);
}
}
}
public void ExportHomeToText()
{
DirectoryInfo HomeDir = new DirectoryInfo(FilePrep.HomeDirectory);
foreach (FileInfo File in HomeDir.GetFiles())
{
DataRow fileRow = _ComboDataTable.NewRow();
XDocument xmlDoc = XDocument.Load(HomeDir + File.Name);
InsuredOrPrincipal[] insured = xmlDoc.Root
.Descendants("InsuredOrPrincipal")
.Select(x => new InsuredOrPrincipal(x))
.Where(ip => ip.InsuredOrPrincipalInfo.InsuredOrPrincipalRoleCd == "Insured")
.ToArray();
foreach (var person in insured)
{
fileRow["First_Name"] = person.GeneralPartyInfo.NameInfo.PersonName.GivenName;
fileRow["Last_name"] = person.GeneralPartyInfo.NameInfo.PersonName.Surname;
fileRow["Address1"] = person.GeneralPartyInfo.Addr.Address1;
fileRow["City"] = person.GeneralPartyInfo.Addr.City;
fileRow["State"] = person.GeneralPartyInfo.Addr.State;
fileRow["Zip"] = person.GeneralPartyInfo.Addr.Zip;
fileRow["Address2"] = " ";
fileRow["Zip4"] = " ";
fileRow["Match_File"] = File.Name.ToString();
_ComboDataTable.Rows.Add(fileRow);
}
}
ExportDataTable.Write(_ComboDataTable, HomeDir.Parent.FullName.ToString());
}
public void CreateDataTable()
{
_ComboDataTable = new DataTable();
_ComboDataTable.Columns.Add("First_Name", typeof(string));
_ComboDataTable.Columns.Add("Last_Name", typeof(string));
_ComboDataTable.Columns.Add("Address1", typeof(string));
_ComboDataTable.Columns.Add("Address2", typeof(string));
_ComboDataTable.Columns.Add("City", typeof(string));
_ComboDataTable.Columns.Add("State", typeof(string));
_ComboDataTable.Columns.Add("Zip", typeof(string));
_ComboDataTable.Columns.Add("Zip4", typeof(string));
_ComboDataTable.Columns.Add("Match_File", typeof(string));
}
}
}
Comp类看起来像这样。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;
namespace xmlCustomReformat
{
public class InsuredOrPrincipal
{
XElement self;
public InsuredOrPrincipal(XElement self) { this.self = self; }
public GeneralPartyInfo GeneralPartyInfo { get { return _GeneralPartyInfo ?? (_GeneralPartyInfo = new GeneralPartyInfo(self.Element("GeneralPartyInfo"))); } }
GeneralPartyInfo _GeneralPartyInfo;
public InsuredOrPrincipalInfo InsuredOrPrincipalInfo
{ get { return _InsuredOrPrincipalInfo ?? (_InsuredOrPrincipalInfo = new InsuredOrPrincipalInfo(self.Element("InsuredOrPrincipalInfo"))); } }
InsuredOrPrincipalInfo _InsuredOrPrincipalInfo;
}
public class GeneralPartyInfo
{
XElement self;
public GeneralPartyInfo(XElement self) { this.self = self; }
public NameInfo NameInfo { get { return _NameInfo ?? (_NameInfo = new NameInfo(self.Element("NameInfo"))); } }
NameInfo _NameInfo;
public Addr Addr { get { return _Addr ?? (_Addr = new Addr(self.Element("Addr"))); } }
Addr _Addr;
}
public class InsuredOrPrincipalInfo
{
XElement self;
public InsuredOrPrincipalInfo(XElement self) { this.self = self; }
public string InsuredOrPrincipalRoleCd
{
get { return (string)self.Element("InsuredOrPrincipalRoleCd"); }
}
}
public class NameInfo
{
XElement self;
public NameInfo(XElement self) { this.self = self; }
public PersonName PersonName { get { return _PersonName ?? (_PersonName = new PersonName(self.Element("PersonName"))); } }
PersonName _PersonName;
}
public class Addr
{
XElement self;
public Addr(XElement self) { this.self = self; }
public string Address1
{
get { return (string)self.Element("Addr1"); }
}
public string City
{
get { return (string)self.Element("City"); }
}
public string State
{
get { return (string)self.Element("StateProvCd"); }
}
public string Zip
{
get { return (string)self.Element("PostalCode"); }
}
}
public class PersonName
{
XElement self;
public PersonName(XElement self) { this.self = self; }
public string Surname
{
get { return (string)self.Element("Surname"); }
}
public string GivenName
{
get { return (string)self.Element("GivenName"); }
}
}
}
当然，我导出回到我追加的文本文件。
using System;
using System.Collections.Generic;
using System.Text;
using System.Data;
using System.IO;
using System.Windows.Forms;
namespace xmlCustomReformat
{
public static class ExportDataTable
{
public static void Write(DataTable dt, string filePath)
{
int i = 0;
StreamWriter sw = null;
try
{
sw = new StreamWriter(filePath + "\\Acord_Combined.txt", false);
for (i = 0; i < dt.Columns.Count-1; i++)
{
sw.Write(String.Format("{0,-50}",dt.Columns[i].ColumnName));
}
sw.Write(dt.Columns[i].ColumnName);
sw.WriteLine();
foreach (DataRow row in dt.Rows)
{
object[] array = row.ItemArray;
for (i = 0; i < array.Length - 1; i++)
{
sw.Write(String.Format("{0,-50}",array[i].ToString()));
}
sw.Write(array[i].ToString());
sw.WriteLine();
}
sw.Close();
}
catch (Exception ex)
{
MessageBox.Show("Invalid Operation : \n" + ex.ToString(),
"Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
}
}
}
现在我仍然需要在处理之后将数据追加到相同的xml文件中。我必须将数据去个性化。所以我假设我只需要做集而不是获取。尚不确定此过程的语法。如果您有改进建议，请随时发表评论。