Question

两个表中都有多个具有相同emp id的记录我需要查询

加入条件app.employee_id = fac.empid
app.begindate，应用程序，结束日期，app.percent
max（amt）但我仍然有可能重复记录，因为对于一个员工来说，amt可以是相同的，所以我需要不同的max amt记录。

但我的下面的查询将首先获得最大记录，然后查询begindate date，end date和percent

我想按照上面指定的顺序查询。

SELECT app.amt, fac.email, fac.employee_id, fac.empid, 
                     fac.first_name, fac.last_name, fac.department_id, fac.titlecode,
                     app.begindate, app.enddate, app.percent,
                     app.title_name, app.department_name 
FROM appointment app
LEFT JOIN appointment app2                                    -- self-join to locate max
 ON app.employee_id = app2.employee_id AND app.amt < app2.amt --  of app.amt
INNER JOIN faculty fac ON app.employee_id=fac.empid            -- join to fac
WHERE app2.amt IS NULL                                        -- isolate rows with max(app.amt)
  AND app.begindate <= NOW() 
  AND app.enddate >= NOW() 
  AND app.percent>.50 group by empid

子查询以消除重复记录

0 个答案: