Question

使用Doctrine 1.2，我在从Doctrine_Collection中删除项目时遇到一些问题。

我有一个充满瞬态Doctrine_Records的Doctrine集合。这里$record->delete()和$record->unlink()函数似乎无法正常工作，因为它们使用记录的ID。（哪些瞬态记录没有，因为它们尚未出现在数据库中。）

示例（公司有很多员工）

/* Get a Company that has no Employees yet. */
$company = Doctrine::getTable('Company')->find(1);

/* Add some Employees */
$names = array('Arthur','Bob','Charlie');

foreach ($names as $name) 
{
    $employee = new Employee;
    $employee->name = "Arthur"
    $company->Employee->add($employee);
}

现在，在将任何内容保存到数据库之前，我在$emp中有一名员工，我想从集合中删除。

$emp->delete() /* Does not work when $emp is transient. */

这是什么工作，但我真的怀疑这是要走的路。

foreach($company->Employee as $key => $value)
    if ($emp == $value) 
    {
        $company->Employee->remove($key);
        break;
    }

这不是最简单的方法。有更推荐的方法吗？

Answer 1

我最终为Doctrine_Collection创建了一个子类，并实现了这个函数，它给了我我想要的行为。

   /**
    * Looks up a Doctrine_Record in the collection, and - when found - removes it. It is also compatible with serialised records, as 
    * it tries strict matching (using ===) as well as loose matching (using ==). A strict match precedes a loose match.
    */
   public function removeItem($item)
   {
      if (!($item instanceof Doctrine_Record)) 
      {
         throw new Exception("Error while calling removeItem, trying to remove an item that does not descend from Doctrine_Record");
         return;
      }

      foreach ($this as $key=>$value)
      {
         if ($item === $value)
         {
            /* Strict match found, remove it and return. */
            $this->remove($key);
            return;
         }
         if ($looseMatch === null && $item == $value) $looseMatch = $key;
      }

      /* No strict match found. If a $matchLoose is on, and aloose match was found, remove it. */
      if ($looseMatch !== null) 
      {
         $this->remove($looseMatch);
      } 
      else throw new Exception('No match found trying to remove an item from a collection.');

   }

从Doctrine_Collection中删除项目

1 个答案: