Question

我有一个警报应用程序应该每隔1分钟打印一次Toast消息。但是当它第一次运行时它只会执行一次。

这里是我的代码：

 private class ConnectivityReceiver extends BroadcastReceiver{
        MainActivity  m= new MainActivity ();
            private Timer mTimer;
            private TimerTask mTimerTask;

            @Override
            public void onReceive(Context context, Intent intent) {
                    NetworkInfo info = intent.getParcelableExtra(ConnectivityManager.EXTRA_NETWORK_INFO);
                    PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE); 
                    PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, "YOUR TAG"); 
                    wl.acquire();                               Toast.makeText(context, "Alarm !!!!!!!!!!", Toast.LENGTH_LONG).show(); // Every 1 minute i print the tost message.                        wl.release();


            }
            public void SetAlarm(Context context) 
            { 
             AlarmManager am=(AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
             Intent i = new Intent(context, ConnectivityReceiver.class); 
             PendingIntent pi = PendingIntent.getBroadcast(context, 0, i, 0);  
             am.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), 1000 * 60 * 1, pi); // Millisec * Second * Minute
             } 
             public void CancelAlarm(Context context)  { 
             Intent intent = new Intent(context, ConnectivityReceiver.class); 
             PendingIntent sender = PendingIntent.getBroadcast(context, 0, intent, 0);
             AlarmManager alarmManager = (AlarmManager) context.getSystemService(Context.ALARM_SERVICE);  
             alarmManager.cancel(sender);  
             }
                    }

Answer 1

做一件事，

在第PendingIntent sender = PendingIntent.getBroadcast(context, 0, intent, 0);行

中

替换为PendingIntent sender = PendingIntent.getBroadcast(context, **someUniqueId**, intent, 0);

其中 uniqueId 是整数，您生成或声明为“i ++”，其中i为public static int i;

希望这会起作用

Android应用程序中的警报问题

1 个答案: