Question

我有一个字符串如下;

dim str as string = "this       is    a string      .   "

我想识别那些多个空格字符并用一个空格字符替换。使用替换函数将替换所有这些，那么执行此类任务的正确方法是什么？

Answer 1

import System.Text.RegularExpressions            

dim str as string  = "This is a      test   ."
dim r as RegEx = new Regex("[ ]+")
str = r.Replace(str, " ")

Answer 2

使用Regex类匹配“一个或多个空格”的模式，然后用一个空格替换所有这些实例。

以下是执行此操作的C＃代码：

Regex regex = new Regex(" +");
string oldString = "this       is    a string      .   ";
string newString = regex.Replace(oldString, " ");

Answer 3

我会使用更容易阅读的\ s +修饰符

public Regex MyRegex = new Regex(
      "\\s+",
    RegexOptions.Multiline
    | RegexOptions.CultureInvariant
    | RegexOptions.Compiled
    );


// This is the replacement string
public string MyRegexReplace =   " ";

string result = MyRegex.Replace(InputText,MyRegexReplace);

或者在VB中

Public Dim MyRegex As Regex = New Regex( _
      "\s+", _
    RegexOptions.Multiline _
    Or RegexOptions.CultureInvariant _
    Or RegexOptions.Compiled _
    )


Public Dim MyRegexReplace As String =  " "


Dim result As String = MyRegex.Replace(InputText,MyRegexReplace)

Answer 4

使用正则表达式。正如其他SO用户here

所建议的那样

用字符串中的一个替换多个相同的字符

4 个答案: