Question

我无法获取以下

的记录

TABLE
id | holiday_From | holiday_To
1  | 2012-01-02   | 2012-01-03
1  | 2012-01-11   | 2012-01-16
1  | 2012-01-08   | 2012-01-22
1  | 2012-01-29   | 2012-01-30
1  | 2012-01-08   | 2012-01-11

我试图在某个月内出现假期 - 即

BETWEEN "2012-01-01" AND "2012-01-31"

有一个类似的post，但我无法根据我的需要调整它

RESULT
day (within range) | count() //number of ppl on holiday
DATE               | 3

例如。

SAMPLE OUTPUT
2012-01-02 | 1
2012-01-03 | 1
2012-01-08 | 2
2012-01-09 | 2
2012-01-10 | 2
2012-01-11 | 3
2012-01-12 | 2
2012-01-13 | 2
2012-01-14 | 2
2012-01-15 | 2
2012-01-16 | 2
......

换句话说，我试图获取特定日期的记录数。即有多少人在1日，2日等人休假。

每个月都不在每个月的表中

有什么想法吗？

P.S。这就是我已经拥有的（我在黑暗中拍摄）

SELECT h.holiday_From, h.holiday_To, COUNT( * )
FROM holiday h
JOIN holiday ho ON h.holiday_From
BETWEEN DATE( "2012-01-01" )
AND IF( DATE( "2012-01-31" ) , DATE( "2012-01-31" ) , DATE( "2012-01-01" ) )
GROUP BY h.holiday_From, h.holiday_To

Answer 1

请，不要害怕：））

基于generate days from date range

select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum-1) day everyday from
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(SELECT @rownum:=0) r WHERE @rownum < DAY(LAST_DAY('2012-01-01'))) d, tablename tbl WHERE d.everyday>=tbl.hFrom AND d.everyday<tbl.hTo GROUP BY d.everyday

结果：

2012-01-02  1
2012-01-08  2
2012-01-09  2
2012-01-10  2
2012-01-11  2
2012-01-12  2
2012-01-13  2
2012-01-14  2
2012-01-15  2
2012-01-16  1
2012-01-17  1
2012-01-18  1
2012-01-19  1
2012-01-20  1
2012-01-21  1
2012-01-29  1

ps：我将列重命名为hFrom和hTo

pps：日期范围的更新变体

select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum - 1) day everyday from
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(SELECT @rownum:=0) r WHERE @rownum <= DATEDIFF('2012-01-11','2012-01-01')) d, `test` tbl WHERE d.everyday BETWEEN tbl.hFrom AND tbl.hTo GROUP BY d.everyday

已更新 - 所有工会都缺少2号。它不应该对任何事情产生重大影响。

Answer 2

你尝试过这样的事吗？

http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_last-day

此功能将为您提供一个月的最后一天，无论涉及的变量如月/月/等......

这可能是你遇到的问题。这不太清楚......

SELECT h.holiday_From, h.holiday_To, COUNT( * )
FROM holiday h
JOIN holiday ho 
    ON h.holiday_From BETWEEN DATE( "2012-01-01" ) AND LAST_DAY("2012-01-01" )
GROUP BY h.holiday_From, h.holiday_To

棘手的mysql计数日期范围内每天的出现次数

2 个答案: