Question

说明：

我创建了一个聊天程序，客户端连接服务器。客户端能够加入通道，当它们这样做时，jList（请参阅代码）应该通过DefaultListModel更新（getChannel（）），并且应该显示连接到同一通道的所有其他客户端。我知道getChannel（）;工作，因为我已经调试它（并使用systemoutprint）。我已经有活动频道和用户在线的Jlists，这有效！：）

客户端使用回调方法通知连接到服务器的其他客户端。

我已经完成了一些调试，并且我一直在尝试重复我的代码。

继承代码：

服务器

private Hashtable<String, ArrayList<String>> channels = new Hashtable<String, ArrayList<String>>();

public void connectChannel(String username, String channel) throws RemoteException{ 
    setUsername(username);
    if(isUserRegistered(username)){ 
        if (!channels.containsKey(channel)) {
            String message = "User " + username + " entered the channel";
            channels.put(channel, new ArrayList<String>());
            channels.get(channel).add(username);
            notifyChannelSystem(channel, "SYSTEM", message);
            notifySelf(username, "Write /? for avaliable commands");
            System.out.println("User " + username + " connected to channel " + channel + " which was created");
        }
        else{
            if(channels.get(channel).contains(username)){ 
                notifySelf(username, "Place in channel " + channel);
                System.out.println("User " + username + " connected to channel " + channel + " which the user was already in");
            } 
            else {
                channels.get(channel).add(username);
                String message = "User " + username + " just entered the channel";
                notifyChannelSystem(channel, "SYSTEM", message);   
                System.out.println("User " + username + " connected to channel " + channel + " which was already created by someone else");
          }
        }
    }
            updateJListForActiveChannels();
            updateJListForUsersInChannel();
}

@Override
public ArrayList<String> getUsersInChannel(String channel) throws RemoteException{
    return channels.get(channel);   
}

@Override
public void updateJListForUsersInChannel() throws RemoteException{
    for(Client c : clients){
        c.getJListForUsersInChannel();
    }
}

GUILogic：

DefaultListModel usersInChanDLM = new DefaultListModel();

public ArrayList<String> getUsersInChannel(String channel) throws RemoteException{
    return cf.getUsersInChannel(channel);
}

public DefaultListModel getUsersInChannelAsDefaultListModel(String channel) throws RemoteException{
    if(!(getChannel() == null)){
        for(String a : cf.getUsersInChannel(getChannel())){
            usersInChanDLM.addElement(a);
        }
    }
    return usersInChanDLM;
}

void updateUsersInChannelJlist(JList jList3) throws RemoteException {
    usersInChanDLM.clear();
    for(Client c : cf.getClients()){
        if(!(usersInChanDLM.contains(c.findName()))){
            usersInChanDLM.addElement(c.findName());
        }
    }
    jList3.setModel(usersInChanDLM);
}

GUI： jList：

usersInChannelJList = new javax.swing.JList();
try{
usersInChannelJList.setModel(gl.getUsersInChannelAsDefaultListModel(gl.getChannel()));

usersInChannelJList.setSelectionMode(javax.swing.ListSelectionModel.SINGLE_SELECTION);
}catch(RemoteException ex){
    System.out.println(ex);
}
jScrollPane4.setViewportView(usersInChannelJList);

接口：

服务器：

    void updateJListForUsersInChannel() throws RemoteException;

客户端：

    void getJListForUsersInChannel() throws RemoteException;

**

问题：

**

JList显示当前连接的所有用户，我猜这是因为这个方法

public ArrayList<String> getUsersInChannel(String channel) throws RemoteException{
        return channels.get(channel);   
    }

我想要做的是从所选频道获取包含所有用户的数组。有没有简单的方法可以从频道哈希表中做到这一点？

更新活动频道的JList时出现问题

说明：

继承代码：

问题：

0 个答案: