我一直在尝试使用uthash.h实现哈希表,遵循(优秀)文档我已经能够使用以下代码获取添加和查找函数:
#include <stdio.h>
#include "../src/uthash.h"
struct my_struct
{
int id; /* key */
char name[10];
double height;
UT_hash_handle hh; /* makes this structure hashable */
};
/* hash-table declared as a global variable */
struct my_struct *users = NULL; /* important! initialize to NULL */
void add_user(int user_id, char *name, double height) {
struct my_struct *s;
s = malloc(sizeof(struct my_struct));
s->id = user_id;
strcpy(s->name, name);
s->height = height;
HASH_ADD_INT( users, id, s ); /* id: name of key field */
}
struct my_struct *find_user(int user_id) {
struct my_struct *s;
HASH_FIND_INT( users, &user_id, s ); /* s: output pointer */
return s;
}
int main()
{
add_user(users, 1, "ben", 1.85);
struct my_struct *user;
user = find_user(users, 1);
printf("user id: %d user name: %s height: %g\n", user->id, user->name, user->height);
return 0;
}
这是一个好的开始,但我对将散列的头部声明为全局变量并且想要将其作为参数传递给add和find函数感到不满,例如:
#include <stdio.h>
#include "../src/uthash.h"
struct my_struct
{
int id; /* key */
char name[10];
double height;
UT_hash_handle hh; /* makes this structure hashable */
};
void add_user(struct my_struct *users, int user_id, char *name, double height) {
struct my_struct *s;
s = malloc(sizeof(struct my_struct));
s->id = user_id;
strcpy(s->name, name);
s->height = height;
HASH_ADD_INT( users, id, s ); /* id: name of key field */
}
struct my_struct *find_user(struct my_struct *users, int user_id) {
struct my_struct *s;
HASH_FIND_INT( users, &user_id, s ); /* s: output pointer */
return s;
}
int main()
{
/* hash_table declared as a local variable and passed in as a parameter to
* add_user and find_user functions */
struct my_struct *users = NULL; /* important! initialize to NULL */
add_user(users, 1, "ben", 1.85);
struct my_struct *user;
user = find_user(users, 1);
printf("user id: %d user name: %s height: %g\n", user->id, user->name, user->height);
return 0;
}
此版本在printf上导致SEG错误,看起来没有任何内容添加到哈希表中。无法真正看到第二个版本出错的地方。当然不能要求将所有哈希表声明为全局变量以使其起作用吗?
可能错过了一些明显的东西 - 但我看不出它是什么......
答案 0 :(得分:4)
如果要修改函数内的指针,则必须使用其地址 所以,功能
add_user(struct my_struct *users, int user_id, char *name, double height)
必须是
add_user(struct my_struct **users, int user_id, char *name, double height)
如果没有,指针不会被修改。
当然,在add_user
内使用
HASH_ADD_INT( *users, id, s )