Question

我有一个大字符串，超过1000个单词。我需要的是找到一个单词，然后将一些单词包装成变量。

$in = 'This is a very long sentence, what I need is to find the word "phone" in this sentence, and after that, to wrap some words around it';

我如何实现这一目标：

$out = 'find the word "phone" in this sentence';

所以，正如你所看到的，当我找到＆＃34; phone＆＃34;这个词时，我想在左边和右边展开。这个词的权利。一个真实的例子是，当您在谷歌上进行查询时，如果标题结果如下，您会从网页上获得一些内容，并且查询会以粗体显示。

Answer 1

正则表达方式

如果要突出显示字符串中的某些单词（搜索文本），请执行以下操作。

PHP代码：

 $in = 'This is a very long sentence, what I need is to find the word phone in this sentence, and after that, to wrap some words around it';
 $wordToFind  = 'phone';
 $wrap_before = '<span class="highlight_match">';
 $wrap_after  = '</span>';

 $out = preg_replace("/($wordToFind)/i", "$wrap_before$1$wrap_after", $in);

 // value of $out is now: 
 // This is a very long sentence, what I need is to find the word <span class="highlight_match">phone</span> in this sentence, and after that, to wrap some words around it

CSS代码

由于此示例使用span类包装匹配的文本，因此这是必需的示例CSS代码

 <style type="text/css">
    .highlight_match {
        background-color: yellow;
        font-weight: bold;
    }
 </style>

Answer 2

这是一种方式。我不是说这是最好的方式，但它会起作用。可能有一种正则表达方式可以“更好”或“更好”。

$in = 'This is a very long sentence, what I need is to find the word phone in this sentence, and after that, to wrap some words around it';
$wordToFind = 'phone';
$numWordsToWrap = 3;

$words = preg_split('/\s+/', $in);
if (($pos = array_search($wordToFind, $words)) !== FALSE) {
  $start = ($pos - $numWordsToWrap > 0) ? $pos - $numWordsToWrap : 0;
  $length = (($pos + ($numWordsToWrap + 1) < count($words)) ? $pos + ($numWordsToWrap + 1) : count($words) - 1) - $start;
  $slice = array_slice($words, $start, $length);
  $out = implode(' ', $slice);
  echo $out;
} else echo 'I didn\'t find it';

Answer 3

感谢@DaveRandom，我刚刚改进了代码并重新编写了

<?php

$in = 'This is a very long sentence, what I need is to find the word phone in this sentence, and after that, to wrap some words around it';
$wordToFind = 'words';
$numWordsToWrap = 3;
echo $in;
echo "<br />";
$words = preg_split('/\s+/', $in);

$found_words    =   preg_grep("/^".$wordToFind.".*/", $words);
$found_pos      =   array_keys($found_words);
if(count($found_pos))
{
    $pos = $found_pos[0];
}

if (isset($pos)) 
{
    $start = ($pos - $numWordsToWrap > 0) ? $pos - $numWordsToWrap : 0;
    $length = (($pos + ($numWordsToWrap + 1) < count($words)) ? $pos + ($numWordsToWrap + 1) : count($words)) - $start;
    $slice = array_slice($words, $start, $length);

    $pre_start  =   ($start > 0) ? "...":"";    

    $post_end   =   ($pos + ($numWordsToWrap + 1) < count($words)) ? "...":"";

    $out = $pre_start.implode(' ', $slice).$post_end;
    echo $out;
} 
else 
    echo 'I didn\'t find it';
?>

你们都想重复使用。

再次感谢DaveRandom

Answer 4

这是一个相对简单的例子，说明如何实现这一目标：

<?php

   $in = "blah blah blah test blah blah blah";
   $search = "test";
   $replace = "--- test ---";

   $out = str_replace($search, $replace, $in);

?>

Answer 5

$out=preg_match('/\w+\s+\w+\s+\w+\s+\"phone\"\s+\w+\s+\w+\s+\w+/',$in,$m);
if ($out) $out=$m[0];

如果引号是可选的，并且您希望使用特殊字符的圆顶灵活性

preg_match('/\w+[^\w]+\w+[^\w]+\w+[^\w]+phone[^\w]+\w+[^\w]+\w+[^\w]+\w+/',$in,$m);

如果你想匹配部分单词，请使用

preg_match('/\w+[^\w]+\w+[^\w]+\w+[^\w]+\w*hon\w*[^\w]+\w+[^\w]+\w+[^\w]+\w+/',$in,$m);

匹配＆＃34; hon＆＃34;在电话中

Answer 6

$in = 'This is a very long sentence, what I need is to find the word phone in this     sentence, and after that, to wrap some words around it';

$array = explode(" ", $in);

$how_much = 3;

$search_word = "phone";

foreach ($array as $index => $word) {
    if ($word == $search_word) {
        for ($index1 = 0; $index1 < ($how_much * 2) + 1; $index1++) {
            $key = $index-$how_much+$index1;
            echo $array[$key];
            echo " ";
        }
    }
}

这是一个简单的解决方案。在空格上分解句子，然后在两个方向上显示你的单词+ $ how_much单词。

在字符串中查找某个单词，然后将其环绕

6 个答案: