Question

我正在尝试将XML数据发送到Web服务。但我没有得到任何服务的回应。当我试图通过SOAPUI发送XML时...我得到错误为“Incoming parameter failiure”..任何人都可以检查我的代码并指出我做错了什么..

- (void)viewDidLoad 
{
    NSString *Message = [NSString stringWithFormat: @"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n"
                     "<SOAP-ENV:Envelope \n"
                         "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" \n"
                     "xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" \n" 
                     "xmlns:SOAP-ENC=\"http://schemas.xmlsoap.org/soap/encoding/\" \n"
                     "SOAP-ENV:encodingStyle=\"http://schemas.xmlsoap.org/soap/encoding/\" \n"
                     "xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\"> \n"
                     "<SOAP-ENV:Body> \n"
                     "<XMLGetReportParameters xmlns=\"http://PlusDiagnostics.Schemas.GetReportParameters\"><UserName xmlns="">USERNAME</UserName><Password xmlns="">PASSWORD</Password><List xmlns="">All</List></XMLGetReportParameters>" 
                     "</SOAP-ENV:Body> \n"
                     "</SOAP-ENV:Envelope>" ];

    NSURL *url = [NSURL URLWithString:@"https://pathflexstage.plusdx.com/MobileReporting/GetPathologyReports.svc"];
    NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:url];
    NSString *msgLength = [NSString stringWithFormat:@"%d", [Message length]];
    NSLog(@"message length is %d",[Message length]);

    [theRequest addValue: @"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [theRequest addValue: msgLength forHTTPHeaderField:@"Content-Length"];
    [theRequest setHTTPMethod:@"POST"];
    [theRequest addValue: @"http://tempuri.org/IGetPathologyReports/GetReports" forHTTPHeaderField:@"soapAction"];

    [theRequest setHTTPBody: [Message dataUsingEncoding:NSUTF8StringEncoding]];

    NSString *returnString = [[NSString alloc] initWithData:[NSURLConnection sendSynchronousRequest:theRequest returningResponse:nil error:nil] encoding:NSUTF8StringEncoding];

    // NSLog("return");
    NSLog(@"%@",returnString);

    [super viewDidLoad];
}

Answer 1

您将从服务器接收回复内容，可能是错误。

声明以下内容;

NSURLResponse *response = nil; 
NSError *error = nil;

...然后提出你的要求;

NSString *returnString = [[NSString alloc] initWithData:[NSURLConnection sendSynchronousRequest:theRequest returningResponse:&response error:&error] encoding:NSUTF8StringEncoding];

...如果您随后检查了响应和错误，您应该能够找到问题的路线。

访问ios应用程序中的Web服务

1 个答案: