Question

我想获取ABPerson对象属性的所有标签名称。例如：记录ABPerson定义了三个电话号码：Mobile，Other，Work。我使用labelAtIndex方法获取标签名称，但返回的字符串包含包含在字符 $ !! $ 中的所需值。而不只是返回“移动”我得到这些“_ $！＆lt;”包裹字符。

我有以下代码：

//person object points to ABPerson record from addressBook
ABMultiValue *phoneNumbers = [person valueForProperty:kABPhoneProperty];

NSUInteger count = [phoneNumbers count];

for (int i = 0; i < count; i++) {
    NSLog(@"Phone numbers label: %@ value: %@", [phoneNumbers labelAtIndex:i], [phoneNumbers valueAtIndex:i]);        
}

在日志中我得到以下内容：

2012-01-23 01:14:04.234 FixMyAddressBook[3667:707] Phone numbers label: _$!<Mobile>!$_ value: +327382738273
2012-01-23 01:14:04.370 FixMyAddressBook[3667:707] Phone numbers label: _$!<Work>!$_ value: +3293829328

有人可以指点我，如何获取没有特殊字符的属性的标签名称？

Answer 1

据我所知，您需要获取该项目的本地化标签，您需要确保使用正确的参考代码。

// Grab the right property first
ABMutableMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
CFIndex phoneNumberCount = ABMultiValueGetCount(phoneNumbers);

for(int k = 0; k < phoneNumberCount; k++)
        {

        //Get phone number label by iterating across this
            CFStringRef phoneNumberValue = ABMultiValueCopyValueAtIndex( phoneNumbers, k );

CFStringRef phoneNumberLabel = ABMultiValueCopyLabelAtIndex(phoneNumbers, i);
            CFStringRef phoneNumberLocalizedLabel = ABAddressBookCopyLocalizedLabel( phoneNumberLabel );    
// converts "_$!<Work>!$_" to "work" and "_$!<Mobile>!$_" to "mobile"
//do whatever you want to do here
//release your references
        CFRelease(phoneNumberLocalizedLabel);
CFRelease(phoneNumberValue);
}

获取ABPerson属性的标签名称

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