Question

我有一个mysql全文问题。参考：http://dev.mysql.com/doc/refman/5.0/en/fulltext-boolean.html

SELECT * FROM table WHERE (MATCH (aindex,bindex) AGAINST ('(+apple +juice)' IN BOOLEAN MODE))

此返回14项

SELECT * FROM table WHERE (MATCH (aindex,bindex) AGAINST ('(+apple +pie)' IN BOOLEAN MODE))

此返回36项

SELECT * FROM table WHERE (MATCH (aindex,bindex) AGAINST ('(+apple +pie)|(+apple +juice)' IN BOOLEAN MODE))

此返回1910项，显然，我的查询有问题。如何搜索确切包含(+apple +pie)和(+apple +juice)的字词？我认为应该返回14+36=50items

在我的目的中，我需要联合搜索

(+apple +pie) (+apple +juice) (+apple +macintosh) (+apple +turnover) (+apple +strudel) (+pear +pie) (+pear +juice) (+pear +macintosh) (+pear +turnover) (+pear +strudel)

它应该返回近520项。感谢。

Answer 1

这应该是你想要的：

SELECT 
  * 
FROM 
  table 
WHERE 
  (MATCH (aindex,bindex) AGAINST ('+apple +(pie juice)' IN BOOLEAN MODE))

ETA：错过了我第一次阅读的梨条款。要获得您列出的所有内容，我认为这应该有效：

SELECT 
  * 
FROM 
  table 
WHERE 
  (MATCH (aindex,bindex) AGAINST ('+((apple +(pie juice macintosh turnover strudel)) (pear +(pie juice macintosh turnover strudel)))' IN BOOLEAN MODE));

这应该转化为“必须包含苹果和馅饼，果汁，macintosh，营业额或馅饼或梨以及馅饼，果汁，麦金托什，营业额或馅饼之一。

如果这不起作用，我会这样做：

SELECT 
  * 
FROM 
  table 
WHERE 
  (MATCH (aindex,bindex) AGAINST ('+apple +(pie juice macintosh turnover strudel)' IN BOOLEAN MODE))
UNION
SELECT 
  * 
FROM 
  table 
WHERE 
  (MATCH (aindex,bindex) AGAINST ('+pear +(pie juice macintosh turnover strudel)' IN BOOLEAN MODE));

mysql全文联合词

1 个答案: