我正在逐行读取文件并将每行添加到字符串中。但是,对于每一行,字符串长度增加1,我认为这是由于换行符所致。如何将其从复制中删除。
这是我的代码尝试做同样的事情。
if (inputFile.is_open())
{
{
string currentLine;
while (!inputFile.eof())
while( getline( inputFile, currentLine ) )
{
string s1=currentLine;
cout<<s1.length();
}
[更新说明]我用notepad ++来确定我逐行选择的长度。所以他们显示了123,450,500,120,我的节目显示124,451,501,120。除最后一行外,所有line.length()都显示增加1的值。
答案 0 :(得分:7)
看起来inputFile
具有Windows风格的line-breaks(CRLF),但是你的程序正在拆分类似Unix的换行符(LF)上的输入,因为std::getline()
打破了默认情况下为\n
,将CR(\r
)保留在字符串的末尾。
你需要修剪无关的\r
。这是一种方法,以及一个小测试:
#include <iostream>
#include <sstream>
#include <iomanip>
void remove_carriage_return(std::string& line)
{
if (*line.rbegin() == '\r')
{
line.erase(line.length() - 1);
}
}
void find_line_lengths(std::istream& inputFile, std::ostream& output)
{
std::string currentLine;
while (std::getline(inputFile, currentLine))
{
remove_carriage_return(currentLine);
output
<< "The current line is "
<< currentLine.length()
<< " characters long and ends with '0x"
<< std::setw(2) << std::setfill('0') << std::hex
<< static_cast<int>(*currentLine.rbegin())
<< "'"
<< std::endl;
}
}
int main()
{
std::istringstream test_data(
"\n"
"1\n"
"12\n"
"123\n"
"\r\n"
"1\r\n"
"12\r\n"
"123\r\n"
);
find_line_lengths(test_data, std::cout);
}
输出:
The current line is 0 characters long and ends with '0x00'
The current line is 1 characters long and ends with '0x31'
The current line is 2 characters long and ends with '0x32'
The current line is 3 characters long and ends with '0x33'
The current line is 0 characters long and ends with '0x00'
The current line is 1 characters long and ends with '0x31'
The current line is 2 characters long and ends with '0x32'
The current line is 3 characters long and ends with '0x33'
注意事项:
std::getline()
将返回该流,当false
不再读取时,该流将转换为inputFile
。答案 1 :(得分:1)
那是因为你在MS-Windows下,他们在“\ n”之前添加了一个“\ r”,并且“\ r”没有删除。