Question

现在其他一位程序员写了这个视图来显示6个月的间隔。我如何写这个，以便它显示按月分组的12个月的间隔，但仅限于2011年

我想将其复制为按月分组的12个月的单独视图，但仅限于2012年

CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`%` 
SQL SECURITY DEFINER VIEW `vw_dash_bymonth`AS
select 
  month(from_unixtime(`tbl_services`.`datetime`)) AS` month1`,
  date_format(from_unixtime(`tbl_services`.`datetime`),'%Y') AS` year1`,
  date_format(from_unixtime(`tbl_services`.`datetime`),'%d') AS `day1`,
 `tbl_services`.`datetime` AS `realdate`,sum(`tbl_services`.`gallons`) AS `gallons`,
 count(0) AS `service`,
 round(avg(`tbl_services`.`gallons`),1) AS `average`
from `tbl_services`
where (from_unixtime(`tbl_services`.`datetime`) > (now() - interval 6 month))
group by month(from_unixtime(`tbl_services`.`datetime`))

Answer 1

如果你看一下where子句

where (from_unixtime(`tbl_services`.`datetime`) > (now() - interval 6 month))

我相信这是从6个月前到今天的所有日期。如果您想在2011年12个月，我认为您可以用以下内容替换该行：

where (from_unixtime(`tbl_services`.`datetime`) >= DATE('2011-01-01 00:00:00')) 
  AND (from_unixtime(`tbl_services`.`datetime`) < DATE('2012-01-01 00:00:00'))

虽然我不知道MySQL（只是SQLServer）所以如果这不起作用，希望其他人可以告诉我哪里出错了。

可以简化为：

where (from_unixtime(`tbl_services`.`datetime`) >= '2011-01-01') 
  AND (from_unixtime(`tbl_services`.`datetime`) < '2012-01-01')

Answer 2

SELECT DISTINCT FROM_UNIXTIME('date','%m-%Y') AS month,
COUNT(`id`) AS count
FROM 'blog'
GROUP BY month
ORDER BY month DESC LIMIT 0,12

Answer 3

SELECT
    MONTH( UNIX_TIMESTAMP( t.`datetime`) ) AS month1,
    DATE_FORMAT( UNIX_TIMESTAMP( t.`datetime`), '%Y' ) AS year1,
    DATE_FORMAT( UNIX_TIMESTAMP( t.`datetime`), '%d') AS day1,
    t.`datetime` AS realdate,
    SUM(t.gallons) AS gallons,
    COUNT(*) AS `service`,
    ROUND( AVG( t.gallons ), 1 ) AS `average`
FROM 
      tbl_services AS t
  CROSS JOIN
      ( SELECT 2011 AS YearToCheck
      ) AS c
WHERE t.`datetime` >= UNIX_TIMESTAMP( MAKEDATE( YearToCheck, 1 ) )
  AND t.`datetime` < UNIX_TIMESTAMP( MAKEDATE( YearToCheck+1, 1 ) )
GROUP BY MONTH( FROM_UNIXTIME( t.`datetime` ) )

SQL视图显示12个月和每年的间隔

3 个答案: