如何在NSUserDefault中存储CCSprite

时间:2012-01-21 14:18:26

标签: cocoa-touch cocos2d-iphone

使用CCSprite子类Creature时遇到一个奇怪的问题。

让我们的对象是生物*生物;

类生物声明 -

@interface Creature : CCSprite <NSCoding>{

    int creatureAge;
    NSString *creatureName;
}

实施

+(id)initializeCreatureWithType:(int)type
{

    Creature *creature = nil;




    creature = [[[super alloc] initWithFile:[NSString stringWithFormat:@"ch%i_default.png",type]]autorelease]; 


    return creature;

}

问题是当我存储我的Creature类对象&#39; creature&#39;在NSUserDefault中使用 -

- (void)encodeWithCoder:(NSCoder *)encoder {

    [encoder encodeObject:self.creatureName forKey:@"creatureName"];
    [encoder encodeInt:self.creatureAge forKey:@"creatureAge"];
}

并用 -

解码
- (id)initWithCoder:(NSCoder *)decoder {
    if((self = [super init])) {

        self.creatureName = [decoder decodeObjectForKey:@"creatureName"];
        self.creatureAge= [decoder decodeIntForKey:@"creatureAge"];
}

然后使用 -

保存生物对象
NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
NSData *myEncodedObject = [NSKeyedArchiver archivedDataWithRootObject:creature];

[defaults setObject:myEncodedObject forKey:@"my_pet"];

负载 -

NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
 NSData *myEncodedObject = [defaults objectForKey:@"my_pet"];
 Creature* newcreature = (Creature *)[NSKeyedUnarchiver unarchiveObjectWithData: myEncodedObject];

问题在于,当我加载它时,我获得先前存储的生物的属性值,但是分配给前一个生物的图像可能不会被复制。因为如果我将newcreature添加到任何CCLayer,它不会显示任何图像,但它会获得前一个生物的属性值。

我现在可以做些什么来获取带图像的新生物?是否需要将图像名称添加为单独的属性???

1 个答案:

答案 0 :(得分:2)

您也可以简单地存储类型,然后按照以下方式存储:

@interface Creature : CCSprite {
    int creatureType;
    int creatureAge;
    NSString *creatureName;
}

+ (id)creatureWithType:(int)type;
- (id)initWithCreatureType:(int)type;
@end

@implementation Creature

+ (id)creatureWithType:(int)type
{
    return [[[[self class] alloc] initWithCreatureType:type] autorelease];
}

- (id)initWithCreatureType:(int)type
{
    self = [super initWithFile:[NSString stringWithFormat:@"ch%i_default.png", type]];
    if (!self) return nil;

    creatureType = type;

    return self;
}

- (id)initWithCoder:(NSCoder *)decoder {
    int type = [decoder decodeIntForKey:@"creatureType"];
    self = [self initWithCreatureType:type];
    if (!self) return nil;

    self.creatureName = [decoder decodeObjectForKey:@"creatureName"];
    self.creatureAge= [decoder decodeIntForKey:@"creatureAge"];

    return self;
}

- (void)encodeWithCoder:(NSCoder *)encoder
{
    [encoder encodeInt:creatureType forKey:@"creatureType"];
    [encoder encodeObject:self.creatureName forKey:@"creatureName"];
    [encoder encodeInt:self.creatureAge forKey:@"creatureAge"];
}
@end

您可能还希望通过属性公开creatureType。请注意,使用名称initializeCreatureWithType:代替creatureWithType:“更多Cocoa”。