Question

我正在尝试将图像上传到PHP页面以及有关图像的其他一些信息，以便PHP页面知道如何处理它。目前，我正在使用它来逃避它：

URL url = new URL("http://www.tagverse.us/upload.php?authcode="+WEB_ACCESS_CODE+"&description="+description+"&userid="+userId);
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setDoOutput(true);
connection.setRequestMethod("POST");

OutputStream os = connection.getOutputStream();
InputStream is = mContext.getContentResolver().openInputStream(uri);
BufferedInputStream bis = new BufferedInputStream(is);
int totalBytes = bis.available();

for(int i = 0; i < totalBytes; i++) {
    os.write(bis.read());
}
os.close();

BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String serverResponse = "";
String response = "";

while((response = reader.readLine()) != null) {
    serverResponse = serverResponse + response;
}
reader.close();
bis.close();

除了拥有GET / POST混合外，还有更优雅的解决方案吗？我觉得好像这很草率，但据我所知，这是一个完全可以接受的解决方案。如果有更好的方法，我会感谢被指向正确的方向。谢谢！

PS：我很熟悉在正常情况下你会如何通过POST与PHP页面进行交互：

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://www.tagverse.us/login.php");

try {
    List<NameValuePair> pairs = new ArrayList<NameValuePair>();
    pairs.add(new BasicNameValuePair("authcode", WEB_ACCESS_CODE));
    pairs.add(new BasicNameValuePair("username", username));
    pairs.add(new BasicNameValuePair("password", password));
    post.setEntity(new UrlEncodedFormEntity(pairs));
    client.execute(post);
}

基本上我想要做的是组合这两种方法，但因为我使用的是HttpURLConnection对象而不是HttpPost对象，所以它并不像仅合并这两种方法那么简单。

谢谢！

Answer 1

您可以尝试查看我为此类似问题添加的答案： https://stackoverflow.com/a/9003674/472747

以下是代码：

byte[] data = {10,10,10,10,10}; // better get this from a file or memory
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost("server url");
ByteArrayBody bab = new ByteArrayBody(data, "image.jpg");
MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
reqEntity.addPart("image", bab);

FormBodyPart bodyPart=new FormBodyPart("formVariableName", new StringBody("formValiableValue"));
reqEntity.addPart(bodyPart);
bodyPart=new FormBodyPart("formVariableName2", new StringBody("formValiableValue2"));
reqEntity.addPart(bodyPart);
bodyPart=new FormBodyPart("formVariableName3", new StringBody("formValiableValue3"));
reqEntity.addPart(bodyPart); 
postRequest.setEntity(reqEntity);
HttpResponse response = httpClient.execute(postRequest);
BufferedReader in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line = null;
while((line = in.readLine()) != null) {
    System.out.println(line);
}

Android：将文件与其他POST字符串一起上传到页面

1 个答案: