从地址c#获取纬度经度

时间:2012-01-20 15:30:10

标签: c# asp.net xml rest

我正在使用地理编码器的网络服务来获取地址,城市和州的纬度和长度。当我使用下面的例子时,我没有得到lat和long。我在这里做错了吗。

请求地址:1125 E. 102nd Street,Los Angeles,CA

这是我的代码:

private void GetLatLongFromAddress(string street, string city, string state)
{
    string geocoderUri = string.Format(@"http://rpc.geocoder.us/service/rest?address={0},{1},{2}", street, city, state);
    XmlDocument geocoderXmlDoc = new XmlDocument();
    geocoderXmlDoc.Load(geocoderUri);
    XmlNamespaceManager nsMgr = new XmlNamespaceManager(geocoderXmlDoc.NameTable);
    nsMgr.AddNamespace("geo", @"http://www.w3.org/2003/01/geo/wgs84_pos#");
    string sLong = geocoderXmlDoc.DocumentElement.SelectSingleNode(@"//geo:long", nsMgr).InnerText;
    string sLat = geocoderXmlDoc.DocumentElement.SelectSingleNode(@"//geo:lat", nsMgr).InnerText;

    Latitude = Double.Parse(sLat);
    Longitude = Double.Parse(sLong);
}

lat和long返回0.我试图添加邮政编码,但这不起作用。是否有更好的网络服务可以为我提供最新的结果。

提前致谢。

3 个答案:

答案 0 :(得分:4)

我经常使用Bing Maps Rest APIs。您可以使用以下请求进行地理编码:

http://dev.virtualearth.net/REST/v1/Locations/CA/adminDistrict/postalCode/locality/addressLine?includeNeighborhood=includeNeighborhood&key=BingMapsKey

您可以在codeproject article I wrote on reactive extensions中看到它正在使用中。

例如,您的地址:

http://dev.virtualearth.net/REST/v1/Locations/US/1125%20E.%20102nd%20Street,%20Los%20Angeles,%20CA?key=Ai9-KNy6Al-r_ueyLuLXFYB_GlPl-c-_iYtu16byW86qBx9uGbsdJpwvrP4ZUdgD

给出以下回复:

{
   "authenticationResultCode":"ValidCredentials",
   "brandLogoUri":"http:\/\/dev.virtualearth.net\/Branding\/logo_powered_by.png",
   "copyright":"Copyright © 2012 Microsoft and its suppliers. All rights reserved. This API cannot be accessed and the content and any results may not be used, reproduced or transmitted in any manner without express written permission from Microsoft Corporation.",
   "resourceSets":[
      {
         "estimatedTotal":1,
         "resources":[
            {
               "__type":"Location:http:\/\/schemas.microsoft.com\/search\/local\/ws\/rest\/v1",
               "bbox":[
                  33.940492293415652,
                  -118.26180800227225,
                  33.948217728557005,
                  -118.24939194889963
               ],
               "name":"1125 E 102ND St, Los Angeles, CA 90002",
               "point":{
                  "type":"Point",
                  "coordinates":[
                     33.944355010986328,
                     -118.25559997558594
                  ]
               },
               "address":{
                  "addressLine":"1125 E 102ND St",
                  "adminDistrict":"CA",
                  "adminDistrict2":"Los Angeles Co.",
                  "countryRegion":"United States",
                  "formattedAddress":"1125 E 102ND St, Los Angeles, CA 90002",
                  "locality":"Los Angeles",
                  "postalCode":"90002"
               },
               "confidence":"High",
               "entityType":"Address",
               "geocodePoints":[
                  {
                     "type":"Point",
                     "coordinates":[
                        33.944355010986328,
                        -118.25559997558594
                     ],
                     "calculationMethod":"Parcel",
                     "usageTypes":[
                        "Display"
                     ]
                  },
                  {
                     "type":"Point",
                     "coordinates":[
                        33.944118499755859,
                        -118.25559997558594
                     ],
                     "calculationMethod":"Interpolation",
                     "usageTypes":[
                        "Route"
                     ]
                  }
               ],
               "matchCodes":[
                  "Good"
               ]
            }
         ]
      }
   ],
   "statusCode":200,
   "statusDescription":"OK",
   "traceId":"81518ba504a3494bb0b62bdb6aa4b291|LTSM002104|02.00.83.500|LTSMSNVM001473, LTSMSNVM001463, LTSMSNVM001452, LTSMSNVM001851, LTSMSNVM001458, LTSMSNVM001462"
}

或者......对于XML数据,请添加o=xml

http://dev.virtualearth.net/REST/v1/Locations/US/1125%20E.%20102nd%20Street,%20Los%20Angeles,%20CA?o=xml&key=Ai9-KNy6Al-r_ueyLuLXFYB_GlPl-c-_iYtu16byW86qBx9uGbsdJpwvrP4ZUdgD

给出了:

<Response>
  <Copyright>Copyright ? 2012 Microsoft and its suppliers. All rights reserved. This API cannot be accessed and the content and any results may not be used, reproduced or transmitted in any manner without express written permission from Microsoft Corporation.</Copyright>
  <BrandLogoUri>http://dev.virtualearth.net/Branding/logo_powered_by.png</BrandLogoUri>
  <StatusCode>200</StatusCode>
  <StatusDescription>OK</StatusDescription>
  <AuthenticationResultCode>ValidCredentials</AuthenticationResultCode>
  <TraceId>b9af8a6b058b455ca9c368b9e32142fe|LTSM002102|02.00.83.500|LTSMSNVM002001, LTSMSNVM001464, LTSMSNVM001451, LTSMSNVM001452, LTSMSNVM001457, LTSMSNVM002052, LTSMSNVM001461</TraceId>
  <ResourceSets>
    <ResourceSet>
      <EstimatedTotal>1</EstimatedTotal>
      <Resources>
        <Location>
          <Name>1125 E 102ND St, Los Angeles, CA 90002</Name>
          <Point>
            <Latitude>33.944355010986328</Latitude>
            <Longitude>-118.25559997558594</Longitude>
          </Point>
          <BoundingBox>
            <SouthLatitude>33.940492293415652</SouthLatitude>
            <WestLongitude>-118.26180800227225</WestLongitude>
            <NorthLatitude>33.948217728557005</NorthLatitude>
            <EastLongitude>-118.24939194889963</EastLongitude>
          </BoundingBox>
          <EntityType>Address</EntityType>
          <Address>
            <AddressLine>1125 E 102ND St</AddressLine>
            <AdminDistrict>CA</AdminDistrict>
            <AdminDistrict2>Los Angeles Co.</AdminDistrict2>
            <CountryRegion>United States</CountryRegion>
            <FormattedAddress>1125 E 102ND St, Los Angeles, CA 90002</FormattedAddress>
            <Locality>Los Angeles</Locality>
            <PostalCode>90002</PostalCode>
          </Address>
          <Confidence>High</Confidence>
          <MatchCode>Good</MatchCode>
          <GeocodePoint>
            <Latitude>33.944355010986328</Latitude>
            <Longitude>-118.25559997558594</Longitude>
            <CalculationMethod>Parcel</CalculationMethod>
            <UsageType>Display</UsageType>
          </GeocodePoint>
          <GeocodePoint>
            <Latitude>33.944118499755859</Latitude>
            <Longitude>-118.25559997558594</Longitude>
            <CalculationMethod>Interpolation</CalculationMethod>
            <UsageType>Route</UsageType>
          </GeocodePoint>
        </Location>
      </Resources>
    </ResourceSet>
  </ResourceSets>
</Response>

因此,给定地址的纬度/经度为(33.9,-118.2)

答案 1 :(得分:1)

Google地图有一个返回lat / long的Web服务API,适用于主要国家/地区。有关示例,请参阅http://maps.google.com/maps/geo?q=1%205th%20ave,new%20york,ny,us。支持不同的输出格式,包括CSV,http://maps.google.com/maps/geo?q=1%205th%20ave,new%20york,ny,us&output=csv,JSON等。

我不熟悉geocoder.us,但谷歌地图绝对适用于美国地址。

编辑1: 有关支持的国家/地区列表,请参阅http://code.google.com/apis/maps/faq.html#whatcountries

编辑2: 为了获得更好的相关性,请参阅以下问题的Google Maps API调用示例:http://maps.google.com/maps/geo?q=1125%20E.%20102nd%20Street,%20Los%20Angeles,%20CA

答案 2 :(得分:1)

按地址获取纬度和经度 - Microsoft BingMapsRESTToolkit

Microsoft 有一个官方 BingMapsRESTToolkit,可帮助您轻松使用 Bing Maps REST Services。为此,您需要安装 BingMapsRESTToolkit NuGet Package

在这里,您对 GeocodeRequest 感兴趣以按地址获取位置。您可以通过将 Query 属性设置为指定地址或将 Address 属性设置为 AddressSimpleAddress 的实例来指定地址。

示例:

var request = new GeocodeRequest();
request.BingMapsKey = "Your Map Key";

request.Query = "The Postal address";

//OR
//request.Address = new SimpleAddress()
//{
//    CountryRegion = "The Country",
//    AddressLine = "The official street line of an address relative to the area",
//    AdminDistrict = "The subdivision name in the country or region for an address",
//    Locality = "The locality, such as the city or neighborhood", 
//    PostalCode = "The postal code",
//};

var result = await request.Execute();
if (result.StatusCode == 200)
{
    var toolkitLocation = (result?.ResourceSets?.FirstOrDefault())
        ?.Resources?.FirstOrDefault() as BingMapsRESTToolkit.Location;
    var latitude = toolkitLocation.Point.Coordinates[0];
    var longitude = toolkitLocation.Point.Coordinates[1];

    // Use latitude and longitude
}

更多信息: