解决了下面的第一个问题，但我仍然需要能够重新调整/重新调整我的代码在将物理文件保存到服务器时所执行的操作。现在已经过去了 存储在数据库中它不起作用..
我在我的代码中看到我没有将重新缩放的图像传递给InputStream，我正在传入原始文件库..可以以某种方式传递newImage作为其不同类型..？
我在从数据库存储/检索图像时遇到了麻烦。最初我有代码允许上传图像，调整大小到所需的尺寸并存储为物理文件。但现在我需要将图像保存到数据库（MS SQL）。
我正在使用MVC2 .NET 3.5
我的代码是一些混搭的不同图片上传对我来说很简单：）
这是用于上传的控制器：
[HttpPost]
public ActionResult ImageUpload(HttpPostedFileBase fileBase, PhotoViewModel photoViewModel)
{
if (photoViewModel.Button == "Upload")
{
photoViewModel.ImageValid = "Valid";
ImageService imageService = new ImageService();
if (fileBase != null && fileBase.ContentLength > 0 && fileBase.ContentLength <= 2097152 && fileBase.ContentType.Contains("image/"))
{
Path.GetExtension(fileBase.ContentType);
var extension = Path.GetExtension(fileBase.FileName);
if (extension.ToLower() != ".jpg" && extension.ToLower() != ".gif") // only allow these types
{
photoViewModel.ImageValid = "Not Valid";
ModelState.AddModelError("Photo", "Wrong Image Type");
return View(photoViewModel);
}
EncoderParameters encodingParameters = new EncoderParameters(1);
encodingParameters.Param[0] = new EncoderParameter(Encoder.Quality, 100L); // Set the JPG Quality percentage
ImageCodecInfo jpgEncoder = imageService.GetEncoderInfo("image/jpeg");
var uploadedimage = Image.FromStream(fileBase.InputStream, true, true);
Bitmap originalImage = new Bitmap(uploadedimage);
Bitmap newImage = new Bitmap(originalImage, 274, 354);
Graphics g = Graphics.FromImage(newImage);
g.InterpolationMode = InterpolationMode.HighQualityBilinear;
g.DrawImage(originalImage, 0, 0, newImage.Width, newImage.Height);
var streamLarge = new MemoryStream();
newImage.Save(streamLarge, jpgEncoder, encodingParameters);
var fileExtension = Path.GetExtension(extension);
string newname;
if (photoViewModel.photoURL != null)
{
newname = photoViewModel.photoURL;
}
else
{
newname = Guid.NewGuid() + fileExtension;
}
//changed this up now, so it stores the image in db as apposed to physical path
photoViewModel.photo = newname;
photoViewModel.ContentType = fileBase.ContentType;
Int32 length = fileBase.ContentLength;
byte[] tempImage = new byte[length];
fileBase.InputStream.Read(tempImage, 0, length);
photoViewModel.ImageData = tempImage;
TempImageUpload tempImageUpload = new TempImageUpload();
tempImageUpload.TempImageData = tempImage;
tempImageUpload.ContentType = photoViewModel.ContentType;
photoViewModel.TempImageId = _service.InsertImageDataBlob(tempImageUpload);
originalImage.Dispose();
streamLarge.Dispose();
return View(photoViewModel);
}
if (fileBase != null)
{
if (fileBase.ContentLength > 0) ModelState.AddModelError("Photo", "Image size too small");
if (fileBase.ContentLength <= 2097152) ModelState.AddModelError("Photo", "Image size too big");
if (fileBase.ContentType.Contains("image/")) ModelState.AddModelError("Photo", "Wrong Image Type");
}
else ModelState.AddModelError("Photo", "Please upload a image");
if (!ModelState.IsValid)
{
photoViewModel.ImageValid = "Not Valid";
return View(photoViewModel);
}
}
return View(photoViewModel);
}
这是我的存储库类：
public int InsertImageDataBlob(TempImageUpload tempImageUpload)
{
int ReturnedPhotoId;
try
{
var phototempdata = new Photo
{
ImageData = tempImageUpload.TempImageData,
contentType = tempImageUpload.ContentType,
dateUploaded = DateTime.Now
};
_db.Photos.InsertOnSubmit(phototempdata);
Save();
ReturnedPhotoId = phototempdata.id;
return ReturnedPhotoId;
}
catch (Exception ex)
{
//ErrorLogging;
}
return 0;
}
数据库中的图像数据字段（图像类型）将填充数据。
任何帮助都会非常感激，我会逐渐变得灰暗!!
由于
答案 0 :(得分：1)
可能它的工作原理..或者不是：-P ....我的代码中的绕过/重新缩放问题的更改（查看我的代码中的注释）：
[HttpPost]
public ActionResult ImageUpload(HttpPostedFileBase fileBase, PhotoViewModel photoViewModel)
{
if (photoViewModel.Button == "Upload")
{
photoViewModel.ImageValid = "Valid";
ImageService imageService = new ImageService();
if (fileBase != null && fileBase.ContentLength > 0 && fileBase.ContentLength <= 2097152 && fileBase.ContentType.Contains("image/"))
{
Path.GetExtension(fileBase.ContentType);
var extension = Path.GetExtension(fileBase.FileName);
if (extension.ToLower() != ".jpg" && extension.ToLower() != ".gif") // only allow these types
{
photoViewModel.ImageValid = "Not Valid";
ModelState.AddModelError("Photo", "Wrong Image Type");
return View(photoViewModel);
}
EncoderParameters encodingParameters = new EncoderParameters(1);
encodingParameters.Param[0] = new EncoderParameter(Encoder.Quality, 100L); // Set the JPG Quality percentage
ImageCodecInfo jpgEncoder = imageService.GetEncoderInfo("image/jpeg");
var uploadedimage = Image.FromStream(fileBase.InputStream, true, true);
Bitmap originalImage = new Bitmap(uploadedimage);
Bitmap newImage = new Bitmap(originalImage, 274, 354);
Graphics g = Graphics.FromImage(newImage);
g.InterpolationMode = InterpolationMode.HighQualityBilinear;
// change from originalImage to newImage
g.DrawImage(newImage, 0, 0, newImage.Width, newImage.Height);
var streamLarge = new MemoryStream();
newImage.Save(streamLarge, jpgEncoder, encodingParameters);
var fileExtension = Path.GetExtension(extension);
string newname;
if (photoViewModel.photoURL != null)
{
newname = photoViewModel.photoURL;
}
else
{
newname = Guid.NewGuid() + fileExtension;
}
//changed this up now, so it stores the image in db as apposed to physical path
photoViewModel.photo = newname;
photoViewModel.ContentType = fileBase.ContentType;
// using the memoryStream streamLarge
// old code: Int32 length = fileBase.ContentLength;
byte[] tempImage = new byte[streamLarge.Length];
// replace fileBase.InputStream with streamLarge
streamLarge.Read(tempImage, 0, length);
photoViewModel.ImageData = tempImage;
TempImageUpload tempImageUpload = new TempImageUpload();
tempImageUpload.TempImageData = tempImage;
tempImageUpload.ContentType = photoViewModel.ContentType;
photoViewModel.TempImageId = _service.InsertImageDataBlob(tempImageUpload);
originalImage.Dispose();
streamLarge.Dispose();
return View(photoViewModel);
}
if (fileBase != null)
{
if (fileBase.ContentLength > 0) ModelState.AddModelError("Photo", "Image size too small");
if (fileBase.ContentLength <= 2097152) ModelState.AddModelError("Photo", "Image size too big");
if (fileBase.ContentType.Contains("image/")) ModelState.AddModelError("Photo", "Wrong Image Type");
}
else ModelState.AddModelError("Photo", "Please upload a image");
if (!ModelState.IsValid)
{
photoViewModel.ImageValid = "Not Valid";
return View(photoViewModel);
}
}
return View(photoViewModel);
}
答案 1 :(得分：1)
我实际上已经使用了这段代码：
photoViewModel.photo = newname;
photoViewModel.ContentType = fileBase.ContentType;
streamLarge.Position = 0;
byte[] tempImage = new byte[streamLarge.Length + 1];
streamLarge.Read(tempImage, 0, tempImage.Length);
photoViewModel.ImageData = tempImage;