Question

我正在尝试使用Joins更新oracle SQL开发人员中的记录。以下是我的查询 -

UPDATE system_info set field_value = 'NewValue' 
FROM system_users users 
JOIN system_info info ON users.role_type = info.field_desc 
where users.user_name = 'uname'

但是，当我尝试执行它时，我收到了以下错误 -

Error report: SQL Error: ORA-00933: SQL command not properly ended 
              00933. 00000 - "SQL command not properly ended"

我尝试删除JOINS

UPDATE system_info info 
SET info.field_value = 'NewValue' 
FROM system_users users 
where users.user_name = 'uname' AND users.role_type = info.field_desc

但仍有同样的错误任何人都可以告诉我错误原因和解决方案

Answer 1

命令末尾的分号;对我造成了同样的错误。

cmd.CommandText = "INSERT INTO U_USERS_TABLE (USERNAME, PASSWORD, FIRSTNAME, LASTNAME) VALUES ("
                + "'" + txtUsername.Text + "',"
                + "'" + txtPassword.Text + "',"
                + "'" + txtFirstname.Text + "',"
                + "'" + txtLastname.Text + "');"; <== Semicolon in "" is the cause.
                                                      Removing it will be fine.

希望它有所帮助。

Answer 2

Oracle不允许在UPDATE语句中连接表。您需要使用共同相关的子选择

重写您的语句

这样的事情：

UPDATE system_info
SET field_value = 'NewValue' 
WHERE field_desc IN (SELECT role_type 
                     FROM system_users 
                     WHERE user_name = 'uname')

有关UPDATE语句的（有效）语法的完整描述，请阅读手册：

http://docs.oracle.com/cd/E11882_01/server.112/e26088/statements_10008.htm#i2067715

Answer 3

不完全是这个问题的实际上下文的情况，但是这个例外可以通过下一个查询重现：

INSERT INTO t2 a
  SELECT
  GROUP_CONCAT(IF (criteria = 11,record,NULL)) AS Label_u,
  GROUP_CONCAT(IF (criteria = 12,record,NULL)) AS Label_v,
  GROUP_CONCAT(IF (criteria = 13,record,NULL)) AS Label_w,
  GROUP_CONCAT(IF (criteria = 14,record,NULL)) AS Label_x,
  GROUP_CONCAT(IF (criteria = 15,record,NULL)) AS Label_y,
  GROUP_CONCAT(IF (criteria = 16,record,NULL)) AS Label_z
  FROM mytable b
  WHERE a .user field = b.user
  GROUP BY USER
  ORDER BY USER;;

       I have tried many - Can someone help me find a functional query to do this?

单词update users set dismissal_reason='he can't and don't want' where userid=123和can't中的单引号打破了字符串。如果字符串只有一个内部引用，例如'他不希望'oracle抛出更多相关引用的字符串未正确终止错误，但是如果两个 SQL命令未正确结束则抛出。

摘要：检查您的查询是否有双引号。

Answer 4

您的查询应该是

UPDATE table_name
SET column1=value, column2=value2,...
WHERE some_column=some_value

您可以查看以下问题寻求帮助

SQL update query using joins？

Answer 5

它在oracle上非常真实，而sql是“用户”是保留字只是改变它，如果你愿意改变它，它会为你提供最好的服务

UPDATE system_info set field_value = 'NewValue'

FROM system_users users JOIN system_info info ON users.role_type = info.field_desc where users.user_name = 'uname'

SQL错误：ORA-00933：SQL命令未正确结束

5 个答案: