所有
我有两个Web应用程序,Web1和Web2,部署在我的tomcat服务器上。我希望Web1中的类在Web2中调用类的方法。一种方法是使用webservice。有没有其他方法类似于在同一个Web应用程序上调用类的方法?。
感谢。
答案 0 :(得分:10)
是。有可能的。它通过使用尝试了相同的servlet容器 getServletContext()。getContext()方法。
首先,您需要在下面的文件中进行更改
(Windows)C:\ Program Files \ Apache Software Foundation \ Tomcat 7.0 \ conf \ context.xml 将crossContext的值设置为true。
<强> context.xml中强>
<Context crossContext="true">
<!-- Default set of monitored resources -->
<WatchedResource>WEB-INF/web.xml</WatchedResource>
<!-- Uncomment this to disable session persistence across Tomcat restarts -->
<!--
<Manager pathname="" />
-->
<!-- Uncomment this to enable Comet connection tacking (provides events
on session expiration as well as webapp lifecycle) -->
<!--
<Valve className="org.apache.catalina.valves.CometConnectionManagerValve" />
-->
</Context>
请注意 crossContext =“true”。
假设您有两个名为 InterServletComm1 和 InterServletComm2 的Web应用程序 在每个Web应用程序中分别具有servlet Servlet1 和 Servlet1 。然后每个servlet中的代码如下:
<强> Servlet1.java 强>
package interServletComm1;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Servlet1
*/
@WebServlet("/Servlet1")
public class Servlet1 extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Servlet1() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
response.setContentType("text/html");
PrintWriter pw = response.getWriter();
request.setAttribute("name", "WebApp1");
ServletContext context = getServletContext().getContext("/InterServletComm2");
RequestDispatcher rd = context.getRequestDispatcher("/Servlet2");
rd.forward(request, response);
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
<强> Servlet2.java 强>
package interServletComm2;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Servlet2
*/
@WebServlet("/Servlet2")
public class Servlet2 extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Servlet2() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
response.setContentType("text/html");
PrintWriter pw = response.getWriter();
String name = (String) request.getAttribute("name");
pw.println("This is web application 2.");
pw.println("<br>The value received from web application one is: " + name);
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
以上代码从 InterServletComm1 发送属性 name ,并在 InterServletComm2 中接收。 如果答案不明确,请告诉我。
答案 1 :(得分:5)
只是搜索了一些文章,使用Tomcat中的CrossContext
切换肯定可以实现上述场景。
在<Context crossContext="true">
然后getServletContext().getContext("/Web2");
。
但是还没试过。
答案 2 :(得分:2)
是的,你可以使用 javax.servlet.ServletContext 和 javax.servlet.RequestDispatcher API来实现。这是它如何从Web1完成:
ServletContext otherContext = servletContext.getContex("/Web2");
RequestDispatcher dispathcer = otherContext.getRequestDispatcher("/a/b.jsp");
dispatcher.forward(request, response);
//or
dispatcher.include(request, response);
答案 3 :(得分:1)
将要在Web应用程序之间共享的类打包到一个单独的jar中。将它们放在common / lib下,这样通用类加载器就可以加载这些类,并且可供两个Web应用程序使用。然后使用jndi在web2中公开实例,从web1中查找它们并调用方法。
答案 4 :(得分:0)
实际上并非如此简单。您可以将app1中的类共享和导入app2,但也许它们都与其他类链接。因此,除了用于进行计算的bean之类的小型服务之外,这个想法并不是那么好。 ppl有很多原因使用Web服务;)。