Question

我想使用GSON将其反序列化为Post列表，但无法弄清楚如何告诉GSON如何忽略根元素“posts”（作为其对象）并只处理数组。 / p>

我有：

Type postTypeList = new TypeToken<List<Post>>(){}.getType();

JsonParser jsonParser = new JsonParser();
JsonElement jsonElement = jsonParser.parse(myJSONString);
JsonObject postsRootObj = jsonElement.getAsJsonObject();

List<Post> postList = gson.fromJson(postsRootObj.get("posts"), postTypeList);

但是我宁愿不拥有整个JsonParser，我宁愿直接将它传递给gson.fromJson函数..有没有办法做到这一点？

{ "posts":
  [      

        {
       "username": "John",  
       "message": "I'm back",
       "time": "2010-5-6 7:00:34"
        "validator":[{
                        "prog": "Name1",
                        "name": "Name2",
                        "computername": "Name3",
                        "date": "2010-11-20 19:39:55"
                      }]
        }
      ,

        {
          "username": "Smith",
          "message": "I've been waiting",
          "time": "2010-4-6 10:30:26"
           "validator":[{
                        "prog": "Name1",
                        "name": "Name2",
                        "computername": "Name3",
                        "date": "2010-11-20 19:39:55"
                      }]

       }
]}

Answer 1

创建一个包含类，其中List<Post>为其成员

public class PostList{
private List<Post> posts;
// getter and setters for posts
}

然后以类似的方式使用fromJson

List<Post> postList = gson.fromJson(myJSONString,PostList.class);

Answer 2

上面有一个修正。用法应该是：

 PostList postList = gson.fromJson(myJSONString,PostList.class);
 Post post = postlist.get(index) //index is the index of list you want to access

虽然JSON源是对象，但GSON反序列化为数组

2 个答案: