我正在使用Jasmin,Simon和jasmin-simon测试骨干视图。
以下是代码:
var MessageContainerView = Backbone.View.extend({
id: 'messages',
initialize: function() {
this.collection.bind('add', this.addMessage, this);
},
render: function( event ) {
this.collection.each(this.addMessage);
return this;
},
addMessage: function( message ) {
console.log('addMessage called', message);
var view = new MessageView({model: message});
$('#' + this.id).append(view.render().el);
}
});
实际上,我的所有测试都通过了一次。我想检查每当我向addMessage
添加项目时都会调用this.collection
。
describe('Message Container tests', function(){
beforeEach(function(){
this.messageView = new Backbone.View;
this.messageViewStub = sinon.stub(window, 'MessageView').returns(this.messageView);
this.message1 = new Backbone.Model({message: 'message1', type:'error'});
this.message2 = new Backbone.Model({message: 'message2', type:'success'});
this.messages = new Backbone.Collection([
this.message1, this.message2
]);
this.view = new MessageContainerView({ collection: this.messages });
this.view.render();
this.eventSpy = sinon.spy(this.view, 'addMessage');
this.renderSpy = sinon.spy(this.messageView, 'render');
setFixtures('<div id="messages"></div>');
});
afterEach(function(){
this.messageViewStub.restore();
this.eventSpy.restore();
});
it('check addMessage call', function(){
var message = new Backbone.Model({message: 'newmessage', type:'success'});
this.messages.add(message);
// TODO: this fails not being called at all
expect(this.view.addMessage).toHaveBeenCalledOnce();
// TODO: this fails similarly
expect(this.view.addMessage).toHaveBeenCalledWith(message, 'Expected to have been called with `message`');
// these pass
expect(this.messageView.render).toHaveBeenCalledOnce();
expect($('#messages').children().length).toEqual(1);
});
});
正如您所见,确实调用了addMessage
。 (它会记录到控制台,并按原样调用this.messageView
。我在为addMessage
个电话进行间谍活动时会错过什么?
谢谢,Viktor
答案 0 :(得分:9)
我不确定,但据我了解,会发生以下情况:
initialize
函数并将view.addMessage
绑定到您的集合。 view.addMessage
,这意味着你用间谍功能覆盖它。执行此操作不会影响存储在集合事件存储中的功能。所以他们的测试存在一些问题。你认为有很多依赖,你没有嘲笑。您创建了一堆额外的Backbone模型和集合,这意味着您不仅可以测试您的视图,还可以测试Backbones集合和模型功能。
您不应该测试collection.bind
是否有效,但是您已使用参数bind
'add', this.addMessage, this
initialize: function() {
//you dont
this.collection.bind('add', this.addMessage, this);
},
所以,很容易模仿集合:
var messages = {bind:function(){}, each:function(){}}
spyOn(messages, 'bind');
spyOn(messages, 'each');
this.view = new MessageContainerView({ collection: messages });
expect(message.bind).toHaveBeenCalledWith('bind', this.view.addMessage, this.view);
this.view.render()
expect(message.each).toHaveBeenCalledWith(this.view.addMessage);
... and so on
这样做只测试代码并且不依赖于Backbone。
答案 1 :(得分:6)
正如安德烈亚斯在第3点所说:
Then you spy on view.addMessage which means you overwrite it with a spy function. Doing this will have no effect on the function that is stored in the collection event store.
对这个问题的直接回答,无视安德烈亚斯建议的所有令人敬畏的重构,都会像MessageContainerView.prototype.addMessage
那样窥探:
describe('Message Container tests', function(){
beforeEach(function(){
this.messageView = new Backbone.View;
this.messageViewStub = sinon.stub(window, 'MessageView').returns(this.messageView);
this.message1 = new Backbone.Model({message: 'message1', type:'error'});
this.message2 = new Backbone.Model({message: 'message2', type:'success'});
this.messages = new Backbone.Collection([
this.message1, this.message2
]);
// Here
this.addMessageSpy = sinon.spy(MessageContainerView.prototype, 'addMessage');
this.view = new MessageContainerView({ collection: this.messages });
this.view.render();
this.eventSpy = sinon.spy(this.view, 'addMessage');
this.renderSpy = sinon.spy(this.messageView, 'render');
setFixtures('<div id="messages"></div>');
});
afterEach(function(){
this.messageViewStub.restore();
MessageContainerView.prototype.addMessage.restore();
});
it('check addMessage call', function(){
var message = new Backbone.Model({message: 'newmessage', type:'success'});
this.messages.add(message);
// TODO: this fails not being called at all
expect(this.addMessageSpy).toHaveBeenCalledOnce();
// TODO: this fails similarly
expect(this.addMessageSpy).toHaveBeenCalledWith(message, 'Expected to have been called with `message`');
// these pass
expect(this.messageView.render).toHaveBeenCalledOnce();
expect($('#messages').children().length).toEqual(1);
});
});
无论如何,我建议实施Andreas的建议。 :)