Gematria带有一个单词列表

时间:2012-01-19 03:06:09

标签: python string counting

我是编程新手。我试图将一个数字(由用户给出)与文件中单词的数值相匹配。示例a = 1。 b = 2,c = 3,A = 1,B = 2,因此如果用户输入“2”,则输出将是列表中与2匹配的所有单词。

userinput = raw_input("Please, enter the gematric value of the word: ")
inputfile = open('c:/school/dictionarytest.txt', 'r')
inputfile.lower()
output = []
for word in inputfile:
    userinput = ord(character) - 96
    output.append(character)
    print output
inputfile.close()

我在这方面有些新鲜,语法并不那么熟悉。有人可以帮忙吗?谢谢

Edit1-示例用户输入数字7.如果单词bad(b = 2,a = 1,d = 4)在列表中,则输出将为“bad”,以及与添加相匹配的任何其他单词他们的角色。

2 个答案:

答案 0 :(得分:1)

以下是包含详细描述的评论的代码:

# ask user for an input until an integer is provided
prompt = "Please, enter the gematric value of the word: "
while True: # infinite loop
    try:        
        # ask user for an input; convert it to integer immediately
        userinput = int(raw_input(prompt))
    except ValueError: # `int()` can't parse user input as an integer
        print('the gematric value must be an integer. Try again')
    else:
        break # got an integer successfully; exit the loop

# use `with` statement to close the file automatically
# `'r'` is default; you don't need to specify it explicitly
with open(r'c:\school\dictionarytest.txt') as inputfile:
    #XXX inputfile.lower() # WRONG!!! file object doesn't have .lower() method

    # assuming `dictionarytest.txt` has one word per line
    for word in inputfile: # read the file line by line
        word = word.strip() # strip leading/trailing whitespace
        if gematric_value(word) == userinput:
           print(word) # print words that match user input

gematric_value()函数在哪里:

def gematric_value(word):
    """Sum of numerical values of word's characters.

    a -> 1, b -> 2, c -> 3; A -> 1, B -> 2, etc
    """
    # word is a string; iterating over it produces individual "characters"
    # iterate over lowercased version of the word (due to A == a == 1)
    return sum(ord(c) - ord('a') + 1 for c in word.lower())

注意:请勿在代码中使用上述注释样式。仅用于教育目的是可以接受的。您应该假设您的代码的读者熟悉Python。

答案 1 :(得分:-1)

您没有阅读文件

inputfile = open('c:/school/dictionarytest.txt', 'r')
file_input = inputfile.readlines().lower()
for character in file_input:
          if userinput == ord(character)-96:
                    output.append(character)