Question

我有

下的方法

 private int SaveRecord(PartnerViewLog partnerViewLog, PortalConstant.DataSourceType DataSourceType, Func<IDataAccess, PartnerViewLog, int> chooseSelector)
            {
                int results = -1;

                var dataPlugin = DataPlugins.FirstOrDefault(i => i.Metadata["SQLMetaData"].ToString() == DataSourceType.EnumToString());

                if (dataPlugin != null)
                {
                    results = chooseSelector(dataPlugin.Value, partnerViewLog);
                }
                return results;
            }

我在

下调用它

public int SavePartnerViewLog(PartnerViewLog partnerViewLog, PortalConstant.DataSourceType DataSourceType)
        {
            return SaveRecord(partnerViewLog, DataSourceType, (i, u) => i.SavePartnerViewLog(partnerViewLog));
        }

可以想象出PartnerViewLog是一个类。现在我想把函数SaveRecord作为通用的，其中类名可以是什么？

怎么做？

Answer 1

尝试以下方法：

private int SaveRecord<T>(T record, PortalConstant.DataSourceType dataSourceType, Func<IDataAccess, T, int> chooseSelector)
{
    int results = -1;

    var dataPlugin = DataPlugins.FirstOrDefault(i => i.Metadata["SQLMetaData"].ToString() == dataSourceType.EnumToString());

    if (dataPlugin != null)
    {
        results = chooseSelector(dataPlugin.Value, record);
    }

    return results;
}

Answer 2

private int SaveRecord<T>(T partnerViewLog, PortalConstant.DataSourceType dataSourceType, Func<IDataAccess, T, int> chooseSelector) 
{
    ...
}

其他所有事情都是一样的

如何使下面的代码通用？

2 个答案: