Question

我创建了一个简单的数据库，用于将数据列表插入到我的示例dB中，但是当我想将数据发送到数据库时，它会给我这个错误

01-17 15：30：43.015：ERROR /数据库（822）：在准备'INSERT INTO friends values（Sharma，SaiGeetha，18）;“”'时，在0x276e50上失败1（没有这样的专栏：Sharma） / p>

供参考，我正在粘贴代码

sampleDB =  this.openOrCreateDatabase(SAMPLE_DB_NAME, MODE_PRIVATE, null);
                ArrayList<String>FirstName = new ArrayList<String>();
                ArrayList<String>LastName = new ArrayList<String>();
                ArrayList<Integer >Age = new ArrayList<Integer>();
                   FirstName.add("SaiGeetha");

                   FirstName.add("Vivek");
                   FirstName.add("Rahul");
                   LastName.add("Sharma");

                   LastName.add("Lilani");
                   LastName.add("Lami");
                    Age.add(18);

                   Age.add(20);
                   Age.add(23);

                sampleDB.execSQL("CREATE TABLE IF NOT EXISTS " +
                        SAMPLE_TABLE_NAME +
                        " (LastName VARCHAR, FirstName VARCHAR," +
                        "  Age INT(3));");

                for(int i=0;i<3;i++)
                {
                    sampleDB.execSQL("INSERT INTO " +


    enter code here

                        SAMPLE_TABLE_NAME +
                            " Values("+LastName.get(i)+","+FirstName.get(i)+","+Age.get(i)+");"+"\"\"");
                }

                /*sampleDB.execSQL("INSERT INTO " +
                        SAMPLE_TABLE_NAME +
                        " Values ('Makam','Sai Geetha','India',25);");
                sampleDB.execSQL("INSERT INTO " +
                        SAMPLE_TABLE_NAME +
                        " Values ('Chittur','Raman','India',25);");
                sampleDB.execSQL("INSERT INTO " +
                        SAMPLE_TABLE_NAME +
                        " Values ('Solutions','Collabera','India',20);");*/

                Cursor c = sampleDB.rawQuery("SELECT FirstName, Age FROM " +
                        SAMPLE_TABLE_NAME +
                        " where Age > 10 LIMIT 5", null);

                if (c != null ) {
                    if  (c.moveToFirst()) {
                        do {
                            String firstName = c.getString(c.getColumnIndex("FirstName"));
                            int age = c.getInt(c.getColumnIndex("Age"));
                            Log.e("---LIST FROM DATABASE--","---VALUE---"+firstName);
                            Log.e("---LIST FROM DATABASE--","---VALUE---"+age );

                        }while (c.moveToNext());
                    } 
                }
                sampleDB.close();

            } catch (SQLiteException se )
            {
                Log.e(getClass().getSimpleName(), "Could not create or Open the database");
            } finally {
                if (sampleDB != null) 
                    sampleDB.execSQL("DELETE FROM " + SAMPLE_TABLE_NAME);
                sampleDB.close();
            }

        }

Answer 1

尝试：

sampleDB.execSQL("INSERT INTO " +
SAMPLE_TABLE_NAME +
" Values('"+LastName.get(i)+"','"+FirstName.get(i)+"',"+Age.get(i)+");");

而不是原件。您需要在SQL语句中使用引号传递String值。如果您不引用它们，则假定您引用columns。

如njzk2所述，其他方法的使用更为合适。请看这个例子：http://learnandroid.blogspot.com/2008/01/android-database.html。特别是以下摘录：

public void createRow(String code, String name) {
    ContentValues initialValues = new ContentValues();
    initialValues.put("code", code);
    initialValues.put("name", name);
    db.insert(DATABASE_TABLE, null, initialValues);
}

Answer 2

像这样修改你的SQL：

"INSERT INTO " + SAMPLE_TABLE_NAME + " (LastName, FirstName, Age) Values( "+LastName.get(i)+","+FirstName.get(i)+","+Age.get(i)+")"

如何将数据列表插入Sqlite数据库

2 个答案: