我有一种感觉,我错过了一些非常简单的东西,但是,在这一个功能中:
def triplets(perimeter):
triplets, n, a, b, c = 0 #number of triplets, a, b, c, sides of a triangle, n is used to calculate a triple
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
for item in L: #iterate through the list of primes
if perimeter % item == 0: #check if a prime divides the perimeter
n = perimeter / item
a = n**2 - (n+1)**2 #http://en.wikipedia.org/wiki/Pythagorean_triple
b = 2n*(n+1)
c = n**2 + n**2
if a+b+c == perimeter: #check if it adds up to the perimeter of the triangle
triplets = triplets + 1
return triplets
我收到错误:
for item in L:
^
SyntaxError: invalid syntax
为了完整性,我的整个程序看起来像这样:
import math
def primes(n): #get a list of primes below a number
if n==2: return [2]
elif n<2: return []
s=range(3,n+1,2)
mroot = n ** 0.5
half=(n+1)/2-1
i=0
m=3
while m <= mroot:
if s[i]:
j=(m*m-3)/2
s[j]=0
while j<half:
s[j]=0
j+=m
i=i+1
m=2*i+3
return [2]+[x for x in s if x]
def triplets(perimeter):
triplets, n, a, b, c = 0 #number of triplets, a, b, c, sides of a triangle, n is used to calculate a triple
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
for item in L: #iterate through the list of primes
if perimeter % item == 0: #check if a prime divides the perimeter
n = perimeter / item
a = n**2 - (n+1)**2 #http://en.wikipedia.org/wiki/Pythagorean_triple
b = 2n*(n+1)
c = n**2 + n**2
if a+b+c == perimeter: #check if it adds up to the perimeter of the triangle
triplets = triplets + 1
return triplets
def solve():
best = 0
perimeter = 0
for i in range(1, 1000):
if triplets(i) > best:
best = triplets(i)
perimeter = i
return perimeter
print solve()
我正在使用Python 2.7.1。在for循环之后我有一个分号,primes(n)
函数有效,我觉得它可能是一些愚蠢但我无法弄清楚它是什么导致这种无效的语法。
答案 0 :(得分:15)
您之前缺少一个右括号:
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
# ^ ^ ^ ^^
#nesting count 1 2 3 21
看看我们如何在线下方的“嵌套计数”中没有达到0?
答案 1 :(得分:1)
你错过了一个括号:
L = primes(int(math.sqrt(perimeter)))
^
|
this one
这种情况一直发生在我身上,你只需要看看之前的那条线。
答案 2 :(得分:0)
之前的行中有错误:
L = primes(int(math.sqrt(perimeter))
你有3个开放的parens,但只有两个关闭的parens。
答案 3 :(得分:0)
错误在上面一行 - 你错过了一个近距离的支架:
L = primes(int(math.sqrt(perimeter)))