使用Spring 3的验证表单

时间:2012-01-16 14:49:05

标签: spring validation

我正在Spring 3上创建验证表单,我的问题是,我看到了许多验证表单的例子。我甚至创造了一个。但我的表单传递“result.hasErrors()”方法,即使有错误。

我的代码是:

控制器:

  

package com.esb.sso;

import java.io.*;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLEncoder;

import javax.servlet.http.*;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.validation.BindingResult;
import java.util.Map;

import javax.validation.Valid;

import com.esb.sso.form.LoginForm;
import javax.servlet.http.HttpServletRequest;

/**
 * Handles requests for the application home page.
 */
@Controller
@RequestMapping(value = "/")
public class HomeController {

LoginForm loginForm = new LoginForm();

        model.put("loginForm", loginForm);

        return "home";
    }


@RequestMapping(method = RequestMethod.POST)
public String validation(@Valid LoginForm loginForm, BindingResult result,
        Map model) throws IOException {

    logger.info("Login POST var");

    logger.info(loginForm.getLogin());
    logger.info(loginForm.getPassword());

    if (result.hasErrors()) {
        logger.info("error");
        return "home";
    }

    model.put("loginForm", loginForm);

    return "logged";

}

}

验证

  

包com.esb.sso.form;

import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;

public class LoginForm {

    @NotNull(message = "notNull")
    @Size(min=1, max=50, message="mote charters")
    private String login;

    @NotNull(message = "notNull")
    @Size(min=1, max=50, message="mote charters")
    private String password;

    public void setLogin(String login){
        this.login = login;
    }

    public String getLogin(){
        return login;
    }

    public void setPassword(String password){
        this.password = password;
    }

    public String getPassword(){
        return password;
    }


}

查看:

  

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<html>
<head>
    <title>Home</title>
</head>
<body>
Autoryzacja!!!
<form:form action="" commandName="loginForm">

<table>

<tr>

<td>User Name:<FONT color="red"><form:errors path="login" /></FONT></td>

</tr>

<tr>

<td><form:input path="login" /></td>

</tr>

<tr>

<td>Password:<FONT color="red"><form:errors path="password" /></FONT></td>

</tr>

<tr>

<td><form:password path="password" /></td>

</tr>

<tr>

<td><input type="submit" value="Submit" /></td>

</tr>

</table>

</form:form>
</body>
</html>

的web.xml:

  

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/root-context.xml</param-value>
    </context-param>

    <!-- Creates the Spring Container shared by all Servlets and Filters -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

的servlet上下文:

    <?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->
    <annotation-driven />

    <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
    <resources mapping="/resources/**" location="/resources/" />

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/" />
        <beans:property name="suffix" value=".jsp" />
    </beans:bean>

    <context:component-scan base-package="com.esb.sso" />

    <beans:bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource">
        <beans:property name="basename" value="/WEB-INF/messages" />
    </beans:bean>

</beans:beans>

和messages.properties:

    NotNull.loginForm.login=must not be blank.
NotNull.loginForm.password=must not be blank.
Size.loginForm.login=Login size must be between 1 and 50 charters.
Size.loginForm.password=Password size must be between 1 and 50 charters.

我不知道问题在哪里

Coul'denybody帮帮我?

1 个答案:

答案 0 :(得分:0)

在HomeController中假设复制粘​​贴错误&#34; /&#34;映射方法。

要回答您的问题 - 您必须将LoginForm对象指定为模型属性,以便使用BindingResult绑定对其的验证。以下是正确的代码

public String validation((@ModelAttribute("loginForm") @Valid LoginForm loginForm, BindingResult result, 
        Map model) throws IOException {

有关参考,请参阅documentation