Question

我试图通过python访问wifi界面：在bash中我可以使用以下

/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport -I

-s也可以通过。

我已尝试在python中使用以下内容：

from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])

某些东西绝对不正确 - 正如我得到的回复：

Traceback (most recent call last):
  File "ip3.py", line 5, in <module>
    call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])
  File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 467, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 741, in __init__
    restore_signals, start_new_session)
  File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 1356, in _execute_child
    raise child_exception_type(errno_num, err_msg)
OSError: [Errno 2] No such file or directory: '/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport'

任何想法都会受到欢迎......我只想首先将其打印到屏幕上，保存为阵列等......

我还没有足够高的评价来回答我自己的问题，所以我会在这里说出来！

所以我是傻瓜！

from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport', '-I'])

工作正常。只需删除/usr/sbin/airport

Answer 1

调用第一个参数作为命令和该命令的后续参数。

在你的情况下命令是， /System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport

和命令的两个参数是，

/ usr / sbin / airport
-I

所以，你需要把它称为，

from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport' '/usr/sbin/airport', '-I'])

Answer 2

试试这个

from subprocess import call
 call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport', '/usr/sbin/airport', '-I'])

否则它认为/usr/sbin/airport是第一条路径的一部分。

python子进程调用OSX

2 个答案: