Question

我有这段代码

              String sql = "distinct from com.zrsol.admin.shared.StatesProvinces";
    Session session = sessionFactory.openSession();
    Query query = session.createQuery(sql); 
    List rsList = query.list();
    for (Iterator it = rsList.iterator();

    it.hasNext();) {
        statesProvinces = (StatesProvinces) it.next();
        allStates.add(statesProvinces);
        String state = statesProvinces.getState();
        states.add(state);
    }
    return states;
}

我得到的错误：java.lang.IllegalArgumentException：要遍历的节点不能为空！

如果我从查询中删除这个“distinct”错误消失了，但是我得到了多种状态，我想要一个独特的状态

由于

Answer 1

"select distinct(state) from com.zrsol.admin.shared.StatesProvinces state";

Answer 2

Here's a snippet of hql that we use. (Names have been changed to protect identities)

String queryString = "select distinct f from Foo f inner join foo.bars as b" +
                " where f.creationDate >= ? and f.creationDate < ? and b.bar = ?";
        return getHibernateTemplate().find(queryString, new Object[] {startDate, endDate, bar});

[Reference][1]


  [1]: http://stackoverflow.com/questions/263850/how-do-you-create-a-distinct-query-in-hql

试图在hibernate中实现Distinct

2 个答案: