Question

让我们看看这个架构：

  orders:
    _attributes:    { phpName: Orders, default_table_charset: utf8, default_table_collate: utf8_general_ci }
    id:             ~
    category_id:    { type: integer, size: '10', required: true, defaultvalue: '0', foreigntable: categories, foreignreference: id }
    whatisthis:     { type: longvarchar, required: false }

  categories:
    _attributes: { phpName: Categories }
    id:          ~
    name:        { type: varchar, size: '255', required: true, defaultvalue: '' }
    _uniques:    { index_name: [name] }

我发现我的表中没有定义外键。我使用innoDB所以PK是可能的。或者Propel不应该设置外键？

Answer 1

“ foreingtable ”和“ foreignreference ”应该是骆驼。而category_id'的大小应该与类别的id大小相等。

  orders:
    _attributes:    { phpName: Orders, default_table_charset: utf8, default_table_collate: utf8_general_ci }
    id:             ~
    category_id:    { type: integer, size: '10', required: true, defaultvalue: '0', foreignTable: categories, foreignreRerence: id }
    whatisthis:     { type: longvarchar, required: false }

  categories:
    _attributes: { phpName: Categories }
    id:          ~
    name:        { type: varchar, size: '255', required: true, defaultvalue: '' }
    _uniques:    { index_name: [name] }

Answer 2

您使用的是哪种symfony和推进版本？

假设正在使用Propel 1.x，这里是一对多关系示例：


  musician:
    _attributes: { phpName: Musician }
    id: { phpName: Id, type: INTEGER, size: '9', primaryKey: true, autoIncrement: true, required: true }
    #other fields
  musician_album:
    _attributes: { phpName: MusicianAlbum }
    id: { phpName: Id, type: INTEGER, size: '9', primaryKey: true, autoIncrement: true, required: true }
    musician_id: { phpName: MusicianId, type: INTEGER, size: '9', required: true, foreignTable: musician, foreignReference: id, onDelete: CASCADE, onUpdate: CASCADE }
    #other fields
    _indexes: { musician_id: [musician_id] }

老实说，我更喜欢手动创建数据库表（设置，索引，外键等）然后我使用symfony（假设你使用的是Symfony 1.x）任务来创建模式： / p>

symfony propel:build-schema

Symfony 1.4 Propel：我定义了，但是表中没有定义外键

2 个答案: