innodb事务和用户定义的变量？

Question

START TRANSACTION;
SELECT * FROM tab1 WHERE 1 LIMIT 1;
DELETE FROM tab1 WHERE id="{HOW TO ACCESS ID FROM THE SELECT ABVOE?}"
COMMIT;

我想获取所选行的ID，删除它并将id返回给PHP (mysql_fetch_array());

Answer 1

DELETE FROM tab1 WHERE id = (SELECT id FROM tab1 LIMIT 1);

你的WHERE毫无意义。我不知道查询的目的，但这是你怎么做的。 或者，您可以将第一个查询的结果保存在会话变量中。

SET @result = (SELECT id FROM  tab1 LIMIT 1);

DELETE FROM tab1 WHERE id = @result;