以下函数检索在大学中主修特定主题的活跃用户的朋友列表。数据来自Facebook GRAPH API。 （这个功能工作）......
function getCollegeFriends () {
$config = array(
'appId' => 'XXXXXXXXXXXXX',
'secret' => 'XXXXXXXXXXXXXX',
);
$facebook = new Facebook($config);
$user_id = $facebook->getUser();
try {
$fql = "select uid,name,education from user WHERE uid IN (select uid2 from friend where uid1=($user_id))";
$param = array(
'method' => 'fql.query',
'query' => $fql,
'callback' => ''
);
$fqlResult = $facebook->api($param);
}
catch(Exception $o){
d($o);
}
$friends = $fqlResult;
$friends_BA = array();
foreach ($friends as $friend) {
$isBA = false;
if (is_array($friend['education'])) {
foreach ($friend['education'] as $school) {
if (isset($school)) {
foreach ($school['school'] as $name) {
$lowerName = strtolower($name);
if (strpos($lowerName, 'university of central florida') !== false || strpos($lowerName, 'ucf') !== false) {
$friends_BA[] = $friend['name'];
continue 3; // skip to the next friend
}
}
}
}
}
}
echo '<pre>';
print_r($friends_BA);
echo '</pre>';
}
现在我正在开发一个函数来返回为同一家公司工作的朋友列表，保持相同的工作岗位等。这是我对该功能的不成功：
function getWorkerFriends () {
$config = array(
'appId' => 'XXXXXXXXX',
'secret' => 'XXXXXXXXX',
);
$facebook = new Facebook($config);
$user_id = $facebook->getUser();
try {
$fql = "select uid,name,work_history from user WHERE uid IN (select uid2 from friend where uid1=($user_id))";
$param = array(
'method' => 'fql.query',
'query' => $fql,
'callback' => ''
);
$fqlResult = $facebook->api($param);
}
catch(Exception $o){
d($o);
}
$friends = $fqlResult;
$friends_BA = array();
foreach ($friends as $friend) {
$isBA = false;
if (is_array($friend['work_history'])) {
foreach ($friend['work_history'] as $employer) {
if (isset($employer)) {
foreach ($employer['location'] as $name) {
$lowerName = strtolower($name['company_name']);
if (strpos($lowerName, 'ubs') !== false || strpos($lowerName, 'merion') !== false) {
$friends_BA[] = $friend['name'];
continue 3; // skip to the next friend
}
}
}
}
}
}
echo '<pre>';
print_r($friends_BA);
echo '</pre>';
}
此解决方案只返回一个空数组，但测试用户确实有满足该功能要求的朋友。下面是用户朋友列表的数组。任何有关建议解决方案的帮助将不胜感激。我现在正处于这个问题的第三天：
（注意：每个[OFFSET]是活跃用户的不同朋友：
[124] => Array
(
[uid] => 553325624
[name] => Persons Name
[current_location] => Array
(
[city] => Los Angeles
[state] => California
[country] => United States
[zip] =>
[id] => 110970792260960
[name] => Los Angeles, California
)
[work_history] => Array
(
)
[education] => Array
(
[0] => Array
(
[school] => Array
(
[id] => 111894272160018
[name] => Spanish River Community High School
)
[type] => High School
)
[1] => Array
(
[school] => Array
(
[id] => 110186095670702
[name] => North Broward Preparatory Schools
)
[type] => High School
)
)
)
[125] => Array
(
[uid] => 560613217
[name] => Persons Name
[current_location] => Array
(
[city] => Summit
[state] => New Jersey
[country] => United States
[zip] =>
[id] => 103727996333163
[name] => Summit, New Jersey
)
[work_history] => Array
(
[0] => Array
(
[location] => Array
(
[city] =>
[state] =>
)
[company_name] => Camp High Rocks
[description] =>
[start_date] =>
[end_date] =>
)
)
[education] => Array
(
[0] => Array
(
[school] => Array
(
[id] => 106165586082302
[name] => Summit Senior High School
)
[type] => High School
)
[1] => Array
(
[school] => Array
(
[id] => 6192688417
[name] => Stanford University
)
[year] => Array
(
[id] => 105576766163075
[name] => 2015
)
[type] => College
)
)
)
答案 0 :(得分：0)
每个变量的var_dump，直到找到一个空变量，如下所示 假设你的facebook连接正常，请尝试下面的代码，这应该会给你一些有用的输出。
function getWorkerFriends () {
$friends = $fqlResult;
echo "\$friends <br/>";
var_dump( $friends );
$friends_BA = array();
foreach ($friends as $friend) {
$isBA = false;
echo "\$friend <br />";
var_dump( $friend );
if (is_array($friend['work_history'])) {
foreach ($friend['work_history'] as $employer) {
echo "\$employer <br />";
var_dump( $employer );
if (isset($employer)) {
foreach ($employer['location'] as $name) {
echo "\$name <br />";
var_dump( $name );
$lowerName = strtolower($name['company_name']);
if (strpos($lowerName, 'ubs') !== false || strpos($lowerName, 'merion') !== false) {
$friends_BA[] = $friend['name'];
echo "Continue to next friend! <br />";
continue 3; // skip to the next friend
}
}
}
}
}
}
echo '<pre>';
print_r($friends_BA);
echo '</pre>';
}