如何从另一个string[]
复制string[]
?
假设我有string[] args
。如何将其复制到另一个数组string[] args1
?
答案 0 :(得分:29)
Array.Clone
并只输出结果。Array.Copy
或Array.CopyTo
例如:
using System;
class Test
{
static void Main(string[] args)
{
// Clone the whole array
string[] args2 = (string[]) args.Clone();
// Copy the five elements with indexes 2-6
// from args into args3, stating from
// index 2 of args3.
string[] args3 = new string[5];
Array.Copy(args, 2, args3, 0, 5);
// Copy whole of args into args4, starting from
// index 2 (of args4)
string[] args4 = new string[args.Length+2];
args.CopyTo(args4, 2);
}
}
假设我们从args = { "a", "b", "c", "d", "e", "f", "g", "h" }
开始,结果是:
args2 = { "a", "b", "c", "d", "e", "f", "g", "h" }
args3 = { "c", "d", "e", "f", "g" }
args4 = { null, null, "a", "b", "c", "d", "e", "f", "g", "h" }
答案 1 :(得分:22)
为目标数组分配空间,使用Array.CopyTo():
targetArray = new string[sourceArray.Length];
sourceArray.CopyTo( targetArray, 0 );
答案 2 :(得分:0)
以上答案显示浅层克隆;所以我想我使用序列化添加了一个深层克隆示例;当然,也可以通过循环原始数组并将每个元素复制到一个全新的数组中来完成深度克隆。
private static T[] ArrayDeepCopy<T>(T[] source)
{
using (var ms = new MemoryStream())
{
var bf = new BinaryFormatter{Context = new StreamingContext(StreamingContextStates.Clone)};
bf.Serialize(ms, source);
ms.Position = 0;
return (T[]) bf.Deserialize(ms);
}
}
测试深度克隆:
private static void ArrayDeepCloneTest()
{
//a testing array
CultureInfo[] secTestArray = { new CultureInfo("en-US", false), new CultureInfo("fr-FR") };
//deep clone
var secCloneArray = ArrayDeepCopy(secTestArray);
//print out the cloned array
Array.ForEach(secCloneArray, x => Console.WriteLine(x.DateTimeFormat.DateSeparator));
//modify the original array
secTestArray[0].DateTimeFormat.DateSeparator = "-";
Console.WriteLine();
//show the (deep) cloned array unchanged whereas a shallow clone would reflect the change...
Array.ForEach(secCloneArray, x => Console.WriteLine(x.DateTimeFormat.DateSeparator));
}