PHP：cookie解析错误

Question

当cookie存在时，我对cookie上的文本有问题，我收到一个错误：“解析错误：语法错误，意外T_VARIABLE，期待” if $_COOKIE['style'] == 'styles2'

<?php 
    if (!isset($_COOKIE['style']))
        echo "<option value='styles' selected>Style 1</option>
              <option value='styles2'>Style 2</option>";
    else{
        if $_COOKIE['style'] == 'styles2'
            echo "<option value='styles'>Style 1</option>
                  <option value='styles2' selected>Style 2</option>";
        else
            echo "<option value='styles' selected>Style 1</option>
                  <option value='styles2'>Style 2</option>";
    }
?>

Answer 1

表达式需要括号：

if ( $_COOKIE['style'] == 'styles2')

Answer 2

不要重复自己。

<?php 
$style = '';
if (isset($_COOKIE['style'])) $style = $_COOKIE['style'];
?>
<option value='styles'>Style 1</option> 
<option value='styles2'<?php if ($style == 'styles2') { ?> selected<?php } ?>>Style 2</option>