对于UIImage的非透明部分，UIImageView像素完美的“触摸开始”

Question

开发iphone app，我使用了UIImageview，并设置了不规则形状的图像

// uiimageview type shutter
shutter = [[UIImageView alloc] initWithFrame:CGRectMake(0,0,320,32.5)];

//setting image on shutter
UIImage* shutterimg = [UIImage imageNamed:@"trayshutter.png"];
[shutter setImage:shutterimg];
// User interaction
shutter.userInteractionEnabled=YES;

我使用touchesbegan

接触

一切都很好，但问题是我也在CGRectMake（即0,0,320,32.5）的imageview占用的所有矩形区域中获取事件，而我只需要在图像上的事件（其形状为 - --- ----- |||||）。

我如何确保我只在图像上获取事件而不是在cgrectmake覆盖的其他区域？

Answer 1

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
  UITouch *touch = [touches anyObject];
  if ([touch view] == yourDesiredImage) {
    // Do something here
  }
}

编辑：也许你可以试试UITapGestureRecognizer：

UITapGestureRecognizer * tapGestureRecognizer = [[UITapGestureRecognizer alloc] init];
[tapGestureRecognizer addTarget:self action:@selector(yourTouchMethod:)];
[tapGestureRecognizer setNumberOfTapsRequired:1];
[shutter addGestureRecognizer:tapGestureRecognizer];
[tapGestureRecognizer release];