Disruptor.NET示例

时间:2012-01-14 06:52:04

标签: c# disruptor-pattern

我正在尝试学习如何使用Disruptor.NET消息框架,但我找不到任何实际的例子。有很多文章都有关于它是如何工作的图片,但我找不到任何实际的内容,并向您展示如何实现这些方法。会是什么样的例子?

2 个答案:

答案 0 :(得分:29)

我为Disruptor-net找不到一个可行的'Hello World'感到沮丧,我一直在努力,直到我找到一个工作 - 见下文。希望它是相当不言自明的。 Console.WriteLine行很容易看到事情的运作方式 - 例如,RingBuffer在启动时创建每个条目实例(这是有意义的)。

希望这有助于任何在.NET上寻求Disruptor帮助的人。

using System;
using System.Linq;
using System.Threading;
using System.Threading.Tasks;
using Disruptor;
using Disruptor.Dsl;

namespace DisruptorTest
{
    public sealed class ValueEntry
    {
        public long Value { get; set; }

        public ValueEntry()
        {
            Console.WriteLine("New ValueEntry created");
        }
    }

    public class ValueAdditionHandler : IEventHandler<ValueEntry>
    {
        public void OnNext(ValueEntry data, long sequence, bool endOfBatch)
        {
            Console.WriteLine("Event handled: Value = {0} (processed event {1}", data.Value, sequence);
        }
    }

    class Program
    {
        private static readonly Random _random = new Random();
        private static readonly int _ringSize = 16;  // Must be multiple of 2

        static void Main(string[] args)
        {
            var disruptor = new Disruptor.Dsl.Disruptor<ValueEntry>(() => new ValueEntry(), _ringSize, TaskScheduler.Default);

            disruptor.HandleEventsWith(new ValueAdditionHandler());

            var ringBuffer = disruptor.Start();

            while (true)
            {
                long sequenceNo = ringBuffer.Next();

                ValueEntry entry = ringBuffer[sequenceNo];

                entry.Value = _random.Next();

                ringBuffer.Publish(sequenceNo);

                Console.WriteLine("Published entry {0}, value {1}", sequenceNo, entry.Value);

                Thread.Sleep(250);
            }
        }
    }
}

答案 1 :(得分:3)

有关Disruptor模式的详细博客文章, The Latency Issue 。它演示了如何开始并详细使用Disruptor。