我正在尝试使用2个按钮（向上和向下）在列表视图中上下移动，突出显示每个项目，具体取决于它在列表视图中的方向。
这是我目前的代码：
Private Sub cmdDown_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdDown.Click
If cmdDown.Tag <> totalRecordsReturned Then
cmdDown.Tag += 1
ListView1.Items(cmdDown.Tag).Selected = True
ListView1.Focus()
End If
End Sub
确实有效但是每次按下按钮都会选择更多项目。我该怎么做才能纠正这个问题？
大卫
答案 0 :(得分：1)
在“设计视图”中，选择“Multiselect = False
”或在代码中添加这一行
ListView1.MultiSelect = False
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
ListView1.MultiSelect = False
End Sub
Private Sub cmdDown_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) _
Handles cmdDown.Click
If cmdDown.Tag <> totalRecordsReturned Then
cmdDown.Tag += 1
ListView1.Items(cmdDown.Tag).Selected = True
ListView1.Focus()
End If
End Sub
答案 1 :(得分：0)
我认为你可以使用这个解决方案。使用listview keyup / keydown：
Private Sub lvSearch_KeyDown(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles lvSearch.KeyDown
If e.KeyCode = Keys.Down Then
If lvSearch.SelectedItems(0).Index < (lvSearch.Items.Count - 1) Then
txtName.Text = lvSearch.Items(lvSearch.SelectedItems(0).Index + 1).SubItems(1).Text
End If
End If
End Sub
Private Sub lvSearch_KeyUp(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles lvSearch.KeyUp
If e.KeyCode = Keys.Up Then
If lvSearch.SelectedItems(0).Index >= 0 Then
txtName.Text = lvSearch.Items(lvSearch.SelectedItems(0).Index).SubItems(1).Text
End If
End If
End Sub
答案 2 :(得分：0)
这非常有用，我将它用于我的项目，但它有点不同。我有一个列表视图，其中第一列是固定索引，因此用户知道列表中有多少项，并且可以按编号引用它们。当向上和向下移动项目时，这是一个问题，因为第1列中的索引号需要保持不变，只更改第2列中的数据。我编写了下面的类，它还支持第2列项的添加，删除和重命名。
Public Class class_ListViewControl
Public ListViewControl_DebugMode As Boolean = True ' to show exceptions in debug mode
Public Sub Init_ListView(ByRef SelectedListView As ListView, ByVal FullRowSelect As Boolean, ByVal ViewMode As View, ByVal Columns() As String)
' Pass the list to modify, two common settings and an array of columns by string name
Try
SelectedListView.View = ViewMode
SelectedListView.FullRowSelect = FullRowSelect
SelectedListView.Columns.Clear()
For i As Integer = 0 To Columns.Length - 1
SelectedListView.Columns.Add(Columns(i), -2)
Next
Catch ex As Exception
If ListViewControl_DebugMode = True Then MsgBox(ex.ToString)
End Try
End Sub
Public Sub MoveListViewItem(ByRef SelectedlistView As ListView, ByVal move As ArrowDirection)
' Pass the listview to edit and the command UP/DOWN
Try
' Select between UP/DOWN arrows
If move = ArrowDirection.Up And SelectedlistView.SelectedItems.Count > 0 Then
Dim selected As ListViewItem = SelectedlistView.SelectedItems(0)
Dim indx As Integer = selected.Index
Dim totl As Integer = SelectedlistView.Items.Count
If indx > 0 Then ' Make sure it's not 0
Dim temp As String = SelectedlistView.Items(indx - 1).SubItems(1).Text ' save the string from the old one first so we can put it in the new location
' move the text in column 2 to the column 2 index below it and place the old text in the next column
SelectedlistView.Items(indx - 1).SubItems(1).Text = SelectedlistView.Items(indx).SubItems(1).Text
SelectedlistView.Items(indx).SubItems(1).Text = temp
' This clears the selection then selects the new index before existing. This allows the user to hit UP again with out having to reselect the item
SelectedlistView.SelectedItems.Clear()
SelectedlistView.Items(indx - 1).Selected = True
End If
ElseIf move = ArrowDirection.Down And SelectedlistView.SelectedItems.Count > 0 Then
Dim selected As ListViewItem = SelectedlistView.SelectedItems(0)
Dim indx As Integer = selected.Index
Dim totl As Integer = SelectedlistView.Items.Count
If indx < SelectedlistView.Items.Count - 1 Then ' if it's less than the max index you can just move the data to the next one
Dim temp As String = SelectedlistView.Items(indx + 1).SubItems(1).Text
SelectedlistView.Items(indx + 1).SubItems(1).Text = SelectedlistView.Items(indx).SubItems(1).Text
SelectedlistView.Items(indx).SubItems(1).Text = temp
' This clears the selection then selects the new index before existing. This allows the user to hit DOWN again with out having to reselect the item
SelectedlistView.SelectedItems.Clear()
SelectedlistView.Items(indx + 1).Selected = True
End If
End If
Catch ex As Exception
If ListViewControl_DebugMode = True Then MsgBox(ex.ToString)
End Try
End Sub
Public Sub EditListViewItem(ByRef SelectedListView As ListView, ByVal EditType As Char, ByVal NewText As String)
' Pass the listview to edit, EditType: ADD = 'A' DELETE = 'D', and Index of item
Try
Dim selected As ListViewItem = Nothing
Dim indx As Integer = 0
If SelectedListView.SelectedIndices.Count > 0 Then ' Only load if something is selected
selected = SelectedListView.SelectedItems(0)
indx = selected.Index
Else
' This is here because you don't need an index selected to add a new item.
selected = Nothing
indx = 0 ' set to 0
End If
Dim total As Integer = SelectedListView.Items.Count
Select Case EditType
Case "A" ' ADD NEW
Dim NewItem As New ListViewItem(CStr(total + 1))
NewItem.SubItems.Add(NewText)
SelectedListView.Items.Add(NewItem)
Case "D" ' DELETE
If selected IsNot Nothing Then ' only execute if something is selected
SelectedListView.Items.Remove(selected) ' Delete the selected item
For i As Integer = 0 To SelectedListView.Items.Count - 1
SelectedListView.Items(i).SubItems(0).Text = CStr(i + 1)
Next
End If
Case "S" ' Save edits
SelectedListView.Items(indx).SubItems(1).Text = NewText
End Select
Catch ex As Exception
If ListViewControl_DebugMode = True Then MsgBox(ex.ToString)
End Try
End Sub
结束班
要使用此类，请在表单1声明中添加：
Private ListViewClass As New class_ListViewControl
然后在Form_Load子中添加初始化：
ListViewClass.Init_ListView(lstv_RFPInfo_Options, True, View.Details, {"#", "Option Title"})
添加按钮示例：
ListViewClass.EditListViewItem(listview1, "A", textbox1.Text)
删除按钮示例：
ListViewClass.EditListViewItem(listview1, "D", "")
