Question

我有一个SQL Server 2008数据库，其中包含一个列（datetime数据类型）的表，可以在下订单时进行记录。

我想运行一个查询，该查询会给出在任何给定日期或日期范围内每小时订单总数的明细，但不确定编写查询的最佳方式。

Answer 1

它应该是：

SELECT DATEPART(HOUR, OrderDate) AS [Hour], COUNT(*) AS [Count]
FROM [Orders]
WHERE OrderDate BETWEEN @StartDate AND @EndDate --or whatever criteria
GROUP BY DATEPART(HOUR, OrderDate)

Answer 2

你可能正在寻找类似的东西：

;WITH OrdersPerHour AS
(
   SELECT
      CAST(OrderDate AS DATE) 'OrderDate',
      DATEPART(HOUR, OrderDate) AS 'Hour',
      SalesAmount
   FROM
      dbo.YourOrderTable
)
SELECT 
   OrderDate, Hour, 
   COUNT(*),          -- number of orders
   SUM(SalesAmount)   -- sum of the amounts for those orders
FROM 
   OrdersPerHour
WHERE
   OrderDate = '20120113'   -- or whatever you're looking for
GROUP BY
   OrderDate, Hour

当您说每小时订单总数时，不确定您是指订单金额的总和 - 或订单数量 - 如果您需要计算，只需使用{ {1}}而不是我放入查询的COUNT(*)。

Answer 3

您可以使用DATEPART和GROUP BY来获取此信息：

SELECT DATEPART(Hour, DateField), COUNT(*)
FROM Orders
WHERE Date = @DateParam -- or your range check here
GROUP BY DATEPART(Hour, Datefield)

Answer 4

我相信它会像这样简单：

    SELECT
         [Hour] = DATEPART(HOUR,DateTimeField)
        ,Orders = COUNT(*)
    FROM
        tblORDERS
    GROUP BY
        DATEPART(HOUR,DateTimeField)

SQL查询一天中的几个小时

4 个答案: