我在这个数据库里面有一个名为accounts
和account
的数据库,另外我在这个数据库里面得到了一个名为players
和player
的数据库。
如何在一个查询中获取这两个表的行数?
我试过这个:
SELECT
SUM(`account`.`account`.`id`) AS 'accounts',
SUM(`player`.`player`) AS 'players';
但它不起作用。
答案 0 :(得分:2)
对两个select语句执行简单的UNION
操作:
SELECT COUNT(*), 'Accounts' FROM Accounts.Account
UNION
SELECT COUNT(*), 'Players' FROM Players.Player
并且您必须使用数据库名称限定每个表,因为它们位于不同的数据库中。
答案 1 :(得分:2)
如果您需要精确的行数(而不是总和),请执行以下操作:
select
(select count(*) from accounts.account) as count1,
(select count(*) from players.player) as count2
或
select count(*) as `count`,"account" as `table` from accounts.account
union all
select count(*) as `count`,"player" as `table` from players.player
答案 2 :(得分:1)
尝试:
SELECT
COUNT(`account`.`id`) AS 'accounts',
COUNT(`player`.`player`) AS 'players'
FROM
`account`,
`player`
答案 3 :(得分:1)
SELECT COUNT(*)
FROM (
SELECT Id
FROM accounts.account
UNION ALL
SELECT player
FROM players.player ) AS BothTables
答案 4 :(得分:0)
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} else {
NSLog(@"lock device");
}