当我尝试使用以下代码运行由echo服务器和android客户端组成的测试时,我总是得到异常msg“socket is closed”。这段代码可以简单地将msg发送到服务器,并从服务器接收消息,但如果你想同时做两件事,它就行不通了......我很好奇为什么它会导致这类问题,如果我希望它能够首先将msg发送到echo服务器
,我应该如何解决它然后从echo服务器接收消息?
// Server IP address
InetAddress serverIp;
// try to connect Server
try {
// set up server IP address
serverIp = InetAddress.getByName("192.168.17.1");
// set up port
int serverPort=12345;
// initiate socket connection
Socket clientSocket=new Socket(serverIp,serverPort);
BufferedOutputStream out = new BufferedOutputStream(clientSocket.getOutputStream());
out.write("Send From Android1111, stitch ".getBytes());
out.flush();
//wait to receive Server's msg
BufferedReader br =new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
total.toString();*/
// Display received msg with Toast
Toast.makeText(getApplicationContext(), br.readLine(), Toast.LENGTH_SHORT ).show();
//close connection
clientSocket.close();
// out.close();
// out = null;
} catch (IOException e) {
// display exception with Toast
Toast.makeText(getApplicationContext(),e.toString(), Toast.LENGTH_SHORT).show();
}
不幸的是,它仍然不起作用......我按照你的指示修改了代码:
// set up Server IP address
serverIp = InetAddress.getByName("192.168.2.2");
// set up Server port
int serverPort=12345;
// initiate socket connection
Socket clientSocket=new Socket(serverIp,serverPort);
// open input and output stream
OutputStream out = clientSocket.getOutputStream();
InputStream in = clientSocket.getInputStream();
//send msg
out.write("Send From Android1111, bitch ".getBytes());
// receive msg from server
byte[] buffer = new byte[in.available()];
in.read(buffer);
String rMsg = new String(buffer);
Toast.makeText(getApplicationContext(), rMsg, Toast.LENGTH_LONG ).show();
//close input and output stream
in.close();
out.close();
//關閉連線
clientSocket.close();
} catch (IOException e) {
// 出錯後顯示錯誤訊息Toast
Toast.makeText(getApplicationContext(),e.toString(), Toast.LENGTH_SHORT).show();
}
为了帮助方便,这里是服务器部分的python编写代码:
# Practice Echo Server Program written in Python
import socket
# host = '' means it binds to any available interface
host = ''
port = 12345
# socket() function returns a socket object whose methods implement the various socket system calls.
s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
# Bind the socket to address.
s.bind((host,port))
# Listen for connections made to the socket. The backlog argument specifies
# the maximum number of queued connections and should be at least 0;
# the maximum value is system-dependent (usually 5), the minimum value is forced to 0.
s.listen(5)
# Accept a connection. The socket must be bound to an address and listening for
# connections. The return value is a pair (conn, address) where conn is a new socket
# object usable to send and receive data on the connection, and address is the address
# bound to the socket on the other end of the connection.
conn, addr = s.accept()
print 'Connected by', addr
# Receive data from the socket. The return value is a string representing the data received.
# The maximum amount of data to be received at once is specified by bufsize. See the Unix
# manual page recv(2) for the meaning of the optional argument flags; it defaults to zero.
# Note For best match with hardware and network realities, the value of bufsize should be
# a relatively small power of 2, for example, 4096.
while 1:
data = conn.recv(1024)
if not data: break
print 'received data is : ', repr(data)
conn.send(data)
conn.close()
答案 0 :(得分:5)
我认为你正在以错误的顺序做正确的事情。可能是服务器太快,当你试图读取响应时,它已经收到并消失了。
遵循教程Reading from and Writing to a Socket
中提供的规则你看到了区别吗?首先打开输入和输出流,然后开始发送您的请求。
我相信如果你坚持这个订单,那就行了。
答案 1 :(得分:0)
我有一个类似的问题,通过编辑gradle.properties文件来解决它,以允许代理连接。我在Nadeem Shaik的https://github.com/facebook/react-native/issues/2726中解释了上述内容。
systemProp.http.proxyHost=proxyHost
systemProp.http.proxyPort=proxyPort
systemProp.https.proxyHost=proxyHost
systemProp.https.proxyPort=proxyPort
答案 2 :(得分:-2)
您的应用程序需要AndroidManifest.xml中的INTERNET权限
<uses-permission android:name="android.permission.INTERNET"/>