RegEx中的grep - bash拾取字符串

Question

我正在尝试运行此

grep -R -l --exclude-dir=merchant --exclude-dir=newport (\w*)\.execute\("ATTACH DATABASE '/include/location\.db' AS (\w*)"\);  * | wc -l

但我一直收到此错误

-sh: syntax error near unexpected token `('

我尝试过这样的括号：

grep -R -l --exclude-dir=merchant --exclude-dir=newport '"\(\w*\)\.execute\("ATTACH DATABASE \'/include/location\.db\' AS \(\w*\)"\);'  *.esp

但是当我点击进入时，它会转到：

>

表示我有一个公开的报价。任何人都可以在这里协助吗？

由于

Answer 1

如何引用整个内容并转义内部引号：

grep -R -l --exclude-dir=merchant --exclude-dir=newport "(\w*)\.execute\(\"ATTACH DATABASE '/include/location\.db' AS (\w*)\"\);"  * | wc -l

Answer 2

这个怎么样 -

grep -R -l --exclude-dir=merchant --exclude-dir=newport '(\w*)\.execute\("ATTACH DATABASE '/include/location\.db' AS (\w*)"\);'  * | wc -l