我的程序运行方式有问题。情况是我有一个表格要求提供日期,然后当点击按钮提交时,将显示具有相同日期的记录。之后有一个按钮提取,如果我点击它,结果将导出为CSV文件。
这是我的代码:
<html>
<h1> TC/GC Per Sales Frequency Bracket </h1>
<body>
<?php
$df = $_POST['df'];
$dt = $_POST['dt'];
$db = 'mds_reports';
if($connect = mysql_connect("172.16.8.32", "mds_reports", "password"))
$connect = mysql_select_db($db);
else die ("Unable to connect".mysql_error());
echo '<form action = "TCFrequencyBracket.php" method = "post">';
echo '<table>';
echo '<tr><td>Date From :</td><td><input name = "df" type = "text" /></td></tr>';
echo '<tr><td>Date To :</td><td><input name = "dt" type = "text" /></td></tr>';
echo '<tr><td><input name = "submit" type = "submit" id = "submit" value = "submit"/></td></tr>';
echo '</table>';
echo '</div>';
echo '</div>';
echo '</form>';
if (isset($_POST['submit']))
{
echo '<table border = "1" cellspacing = "1">';
echo '<th>Restaurant Code</th>';
echo '<th>Restaurant Name</th>';
echo '<th>100 & BELOW</th>';
echo '<th>101-200</th>';
echo '<th>201-300</th>';
echo '<th>301-400</th>';
echo '<th>401-500</th>';
echo '<th>501-600</th>';
echo '<th>601-700</th>';
echo '<th>701-800</th>';
echo '<th>801-900</th>';
echo '<th>901-1000</th>';
echo '<th>1001 & ABOVE</th>';
echo '<th>TOTAL TC</th>';
$sql = "SELECT restaurant_master.code, restaurant_master.name,
COUNT(CASE WHEN mds_orders.GrossTotal < '100'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '100' AND mds_orders.GrossTotal < '200'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '200' AND mds_orders.GrossTotal < '300'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '300' AND mds_orders.GrossTotal < '400'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '400' AND mds_orders.GrossTotal < '500'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '500' AND mds_orders.GrossTotal < '600'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '600' AND mds_orders.GrossTotal < '700'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '700' AND mds_orders.GrossTotal < '800'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '800' AND mds_orders.GrossTotal < '900'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '900' AND mds_orders.GrossTotal < '1000'
THEN 1 END),
COUNT(CASE WHEN mds_orders.GrossTotal >= '1000'
THEN 1 END),
COUNT(mds_orders.GrossTotal)
FROM mds_orders
JOIN restaurant_master
ON mds_orders.RestaurantID = restaurant_master.PKID
WHERE mds_orders.OrderDate BETWEEN '$df' AND '$dt'
AND mds_orders.StatusFKID = 2
GROUP BY restaurant_master.code, restaurant_master.name";
// echo $sql;
echo 'Date select from ' . $df;
echo ' to ' . $dt;
echo '<br /><br />';
$result = mysql_query($sql)
or die("SELECT Error: ".mysql_error());
$num_rows = mysql_num_rows($result);
print "There are $num_rows records.<br>";
echo '<br />';
while ($get_info = mysql_fetch_row($result)){
print "<tr>\n";
foreach ($get_info as $fields)
print "\t<td>$fields</td>\n";
print "</tr>\n";
}
echo '</table>';
echo '<form>';
echo '<div>';
echo '</div>';
echo '<table>';
echo '<br><input name = "extract" type = "submit" id = "extract" value = "extract"/></td><td></br></br>';
echo '<tr><td></table></td></td>';
echo '</form>';
$out = '';
if (isset($_POST['extract'])) {
$out .= $_POST['extract'];
}
$filename = $file."_".date("Y-m-d_H-i",time());
print stripslashes($out);
exit;
}
?>
</body>
</html>`
现在错误是当我尝试打开程序时,即使主页面尚未显示,也已显示提示。此外,文件的内容是代码而不是结果。
答案 0 :(得分:1)
我真的不明白这个问题,但我看到了一些问题:
$out
变量会获得按钮的值$_POST['extract']
,该值始终为extract
,仅此而已。答案 1 :(得分:0)
您必须检查为PHP启用设置的Web服务器。将页面本身作为内容获取的一种方法是在服务器未设置为运行PHP时。然后服务器会提示下载页面而不是运行/执行它。
在解决代码问题之前,请确保您的Web服务器可以正确地提供PHP脚本或文件。
接下来看一下如何存储包含文件的给定代码并检查其扩展名是否为.php。
然后检查您在主页中如何包含该页面或如何访问该页面。