Question

我有以下内容，它生成xmlNodePtr，然后我想将该节点转换为字符串，保留所有xml格式和内容：

std::string toString()
{
  std::string xmlString;

  xmlNodePtr noteKey = xmlNewNode(0, (xmlChar*)"noteKeyword");

  std::vector<Note *>::iterator iter = notesList_.begin();
  while(iter != notesList_.end())
  {
    xmlNodePtr noteNode = xmlNewNode(0, (xmlChar*)"Note");

    xmlNodePtr userNode = xmlNewNode(0, (xmlChar*)"User");
    xmlNodePtr dateNode = xmlNewNode(0, (xmlChar*)"Date");
    xmlNodePtr commentNode = xmlNewNode(0, (xmlChar*)"Comment");

    xmlNodeSetContent(userNode, (xmlChar*)(*iter)->getUser().c_str());
    xmlNodeSetContent(dateNode, (xmlChar*)(*iter)->getDate().c_str());
    xmlNodeSetContent(commentNode, (xmlChar*)(*iter)->getComment().c_str());

    xmlAddChild(noteNode, userNode);
    xmlAddChild(noteNode, dateNode);
    xmlAddChild(noteNode, commentNode);

    xmlAddChild(noteKey, noteNode);

    iter++;
  }

  xmlDocPtr noteDoc = noteKey->doc;

  //this doesn't appear to work, do i need to allocate some memory here?
  //or do something else?
  xmlOutputBufferPtr output;
  xmlNodeDumpOutput(output, noteDoc, noteKey, 0, 1, "UTF-8");

  //somehow convert output to a string?
  return xmlString;
}

我的问题是节点似乎变得很好但我不知道如何将节点转换为std :: string。我也尝试过使用xmlNodeListGetString和xmlDocDumpFormatMemory，但我无法让其中任何一个工作。如何从节点转换为字符串的示例将非常感谢，谢谢。

Answer 1

关键是添加：

  xmlChar *s;
  int size;

  xmlDocDumpMemory((xmlDocPtr)noteKey, &s, &size);

  xmlString = (char *)s;
  xmlFree(s);

Answer 2

试试这个例子：

xmlBufferPtr buf = xmlBufferCreate();

// Instead of Null, you can write notekey->doc
xmlNodeDump(buf, NULL, noteKey, 1,1);
printf("%s", (char*)buf->content);

Ricart y Rambo签名。

如何将xmlNodePtr与所有xml格式化转换为字符串？

2 个答案: