可以直接在第三方应用程序(Android)上打开短信吗?

时间:2012-01-11 19:52:19

标签: android text messages

当发送文本消息时,假设应用程序“myApp”它将在接收方的默认文本消息app中打开。但我想控制接收器的外观(如改变颜色)。无论如何都要发送文本并在本机应用程序'myApp'中读取该文本?或者确定它是从'myApp'发送的,并将消息导入'myApp'。

1 个答案:

答案 0 :(得分:1)

确保您可以接收消息,每当消息到达时,都会创建一个用于输入消息的广播接收器,从而开始显示消息的活动......

public class SMSApp extends IntentReceiver {
    private static final String LOG_TAG = "SMSApp";

    /* package */ static final String ACTION =
            "android.provider.Telephony.SMS_RECEIVED";

    public void onReceiveIntent(Context context, Intent intent) {
        if (intent.getAction().equals(ACTION)) {
            StringBuilder buf = new StringBuilder();
            Bundle bundle = intent.getExtras();
            if (bundle != null) {
                SmsMessage[] messages = Telephony.Sms.Intents.getMessagesFromIntent(intent);
                for (int i = 0; i < messages.length; i++) {
                    SmsMessage message = messages[i];
                    buf.append("Received SMS from  ");
                    buf.append(message.getDisplayOriginatingAddress());
                    buf.append(" - ");
                    buf.append(message.getDisplayMessageBody());
                }
            }
           //start you messages activity 

        Intent i = new Intent();
        i.setClassName("com.test", "com.test.myMessagesAcivity");
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);

        //prepare message text to be sent to the activity via bundle 
        Bundle bundle = new Bundle();
        bundle.putString("message", but.toString());
        i.putExtras(bundle);
        context.startActivity(i);


        }
    }


}

并在您的清单文件中添加这些权限

<uses-permission android:id="android.permission.RECEIVE_SMS" />

<uses-permission android:name="android.permission.SEND_SMS"/>

和这个接收器

<receiver class="SMSApp">

            <intent-filter>

                <action android:value="android.provider.Telephony.SMS_RECEIVED" />

            </intent-filter>

        </receiver>

并从您的应用发送短信

使用此方法

public void eb3atSMS(String phoneNumber, String message)
    {        

        PendingIntent pi = PendingIntent.getActivity(this, 0,
            new Intent(this, **DummyClasshere.class**), 0);                
        SmsManager sms = SmsManager.getDefault();
        sms.sendTextMessage(phoneNumber, null, message, pi, null);        
    }