我尝试了几件事......使用变量和模板,并且进展缓慢。但我只是没有让这个工作 - 我的上下文遇到了麻烦。
输入......
OutPut ......
我修改了我的代码,以下内容可能无法完全正常运行,但会对我尝试过的内容进行分析。
我的第一个问题是 - 我是否走在正确的轨道上?
这是我的上下文问题阻止我的地方。
- 我的输入XML -
<?xml version="1.0"?>
<Account Number="123456">
<Data>
<Table ID="700">
<Record ID="1" SubClass="Person">
<Name.Last>Smith</Name.Last>
<Name.First>John</Name.First>
<Score1>50</Score1>
<Score2>75</Score2>
<Score3>100</Score3>
<Subject1>Math</Subject1>
<Subject2>English</Subject2>
<Subject3>Science</Subject3>
</Record>
<Record ID="2" SubClass="Person">
<Name.Last>Smith</Name.Last>
<Name.First>Jane</Name.First>
<Score1></Score1>
<Score2>77</Score2>
<Score3>80</Score3>
<Subject1>Math</Subject1>
<Subject2>English</Subject2>
<Subject3>Science</Subject3>
</Record>
</Table>
</Data>
</Account>
- 所需的输出XML -
<Out>
<Subject_ENGLISH>1</Subject_ENGLISH>
<Subject_MATH>1</Subject_MATH>
<Subject_SCIENCE>1</Subject_SCIENCE>
<Class_SCORE>75</Class_SCORE>
<Class2_SCORE>50</Class2_SCORE>
<Class3_SCORE>100</Class3_SCORE>
<Subject_ENGLISH>0</Subject_ENGLISH>
<Subject_MATH>1</Subject_MATH>
<Subject_SCIENCE>1</Subject_SCIENCE>
<Class_SCORE></Class_SCORE>
<Class2_SCORE>77</Class2_SCORE>
<Class3_SCORE>80</Class3_SCORE>
</Out>
- 当前不起作用的XSLT -
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
<xsl:output method="xml" encoding="UTF-8"/>
<xsl:template match="Account">
<Out>
<xsl:for-each select="/Account/Data/Table[@ID='700']/Record[@SubClass='Person']>
<xsl:call-template name="Grades">
<xsl:with-param name="Subject">English</xsl:with-param>
</xsl:call-template>
<xsl:call-template name="Grades">
<xsl:with-param name="Subject">Math</xsl:with-param>
</xsl:call-template>
<xsl:call-template name="Grades">
<xsl:with-param name="Subject">Science</xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</Out>
</xsl:template>
<xsl:template name="Grades">
<xsl:param name="Subject"/>
<xsl:for-each select="*[starts-with(name(), 'Subject')][node()=$Subject]">
<xsl:variable name='cr-index'>
<xsl:value-of select ='substring(name(), string-length(name()))'/>
</xsl:variable>
<xsl:call-template name="create-Grades-nodes">
<xsl:with-param name="cr-context" select =".."/>
<xsl:with-param name="Subject">
<xsl:value-of select='$Subject' />
</xsl:with-param>
<xsl:with-param name="cr-index">
<xsl:value-of select='$cr-index'/>
</xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="create-Grades-nodes" match="$cr-context" >
<xsl:param name ="cr-context"/>
<xsl:param name ="Subject"/>
<xsl:param name ="cr-index"/>
<xsl:variable name='cr-score'>
<xsl:value-of select='name($cr-context)/concat("Score", $cr-index)'/>
</xsl:variable>
<xsl:variable name="smallcase" select="'abcdefghijklmnopqrstuvwxyz'" />
<xsl:variable name="uppercase" select="'ABCDEFGHIJKLMNOPQRSTUVWXYZ'" />
<xsl:element name='{concat("Subject_", translate($Subject, $smallcase, $uppercase))}'>
<xsl:choose>
<xsl:when test= '$cr-score > 0'>
<xsl:value-of select = "1"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select = "0"/>
</xsl:otherwise>
</xsl:choose>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
答案 0 :(得分:4)
此转化:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pSubjects">
<s name="English" at="1"/>
<s name="Math" at="2"/>
<s name="Science" at="3"/>
</xsl:param>
<xsl:variable name="vSubjects" select=
"document('')/*/xsl:param[@name='pSubjects']/*"/>
<xsl:variable name="vLower" select=
"'abcdefghijklmnopqrstuvwxyz'"/>
<xsl:variable name="vUpper" select=
"'ABCDEFGHIJKLMNOPQRSTUVWXYZ'"/>
<xsl:template match="/*">
<Out>
<xsl:apply-templates/>
</Out>
</xsl:template>
<xsl:template match="Table[@ID='700']/Record">
<xsl:apply-templates select="*[starts-with(name(), 'Su')]">
<xsl:sort select="$vSubjects[@name = current()]/@at" data-type="number"/>
</xsl:apply-templates>
<xsl:apply-templates select="*[starts-with(name(), 'Sc')]">
<xsl:sort select=
"$vSubjects[@name
= current()/../*[starts-with(name(), 'Su')]
[substring-after(name(), 'Subject')
=
substring-after(name(current()), 'Score')
]
]/@at"
data-type="number"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*[starts-with(name(), 'Su')]">
<xsl:variable name="vgenName" select=
"concat('Subject_',
translate(., $vLower, $vUpper)
)"/>
<xsl:element name="{$vgenName}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
<xsl:template match="*[starts-with(name(), 'Sc')]">
<xsl:variable name="vInd" select=
"$vSubjects[@name
= current()/../*[starts-with(name(), 'Su')]
[substring-after(name(), 'Subject')
=
substring-after(name(current()), 'Score')
]
]/@at"/>
<xsl:variable name="vgenName" select=
"concat('Class',
translate($vInd, '1', ''),
'_SCORE'
)
"/>
<xsl:element name="{$vgenName}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
应用于提供的XML文档:
<Account Number="123456">
<Data>
<Table ID="700">
<Record ID="1" SubClass="Person">
<Name.Last>Smith</Name.Last>
<Name.First>John</Name.First>
<Score1>50</Score1>
<Score2>75</Score2>
<Score3>100</Score3>
<Subject1>Math</Subject1>
<Subject2>English</Subject2>
<Subject3>Science</Subject3>
</Record>
<Record ID="2" SubClass="Person">
<Name.Last>Smith</Name.Last>
<Name.First>Jane</Name.First>
<Score1></Score1>
<Score2>77</Score2>
<Score3>80</Score3>
<Subject1>Math</Subject1>
<Subject2>English</Subject2>
<Subject3>Science</Subject3>
</Record>
</Table>
</Data>
</Account>
生成想要的正确结果:
<Out>
<Subject_ENGLISH>English</Subject_ENGLISH>
<Subject_MATH>Math</Subject_MATH>
<Subject_SCIENCE>Science</Subject_SCIENCE>
<Class_SCORE>75</Class_SCORE>
<Class2_SCORE>50</Class2_SCORE>
<Class3_SCORE>100</Class3_SCORE>
<Subject_ENGLISH>English</Subject_ENGLISH>
<Subject_MATH>Math</Subject_MATH>
<Subject_SCIENCE>Science</Subject_SCIENCE>
<Class_SCORE>77</Class_SCORE>
<Class2_SCORE></Class2_SCORE>
<Class3_SCORE>80</Class3_SCORE>
</Out>