Question

所以，我正在处理（编程语言）中创建游戏突破，但是无法找到检查与蝙蝠碰撞的函数。

到目前为止，我为撞击蝙蝠所写的部分只是将球碰到底座并以相反的方向返回。目前，这场比赛是一个永无止境的现象，球刚刚与墙壁发生碰撞。我要做的是，将球与球棒碰撞。

哦，这是我的作业，所以请指出我正确的方向，而不是为我做。

以下是代码：

// Basic Breakout game
// Code from Matthre Yee-King

// brick position
float brickX;
float brickY;

// brick width and height
float brickH;
float brickW;

// ball position
float ballX;
float ballY;

// ball diameter
float ballD;

// ball direction
float ballDx;
float ballDy;

// bat position
float batX;

//bat width
float batW;
float batH;

//bat colour
float batB;

void setup() {
  size (500, 500, P2D);

  // set sizes of game items
  brickW = 100;
  brickH = 50;
  batW = 100;
  batH = 25;
  ballD = 25;
  batB = 255;

  // random brick position
  brickX = random(0, width - brickW);
  brickY = random (0, height / 2);

  // bat in the centre
  batX = (width/2) - (batW/2);

  // ball atop bat
  ballX = batX + (batW/2);
  ballY = height - batH - (ballD/2);

  // ball movement
  ballDx = random(-5, 5);
  ballDy = -5;
  rectMode(CORNER);
  ellipseMode(CENTER);
}

void draw() {
  // check for ball collision
  // with top or sides of bat
  checkBallAgainstBat();

  // check for ball collision with
  // left right and top walls
  // and bounce
  checkBallAgainstWalls();

  // check ball against brick
  checkBallAgainstBrick();

  // move the ball
  ballX += ballDx;
  ballY += ballDy;
  background(0);

  // draw the bat
  fill(0, 255, 0);
  rect(batX, height - batH, batW, batH);

  // draw the brick
  fill(0, 0, batB);
  batB = (batB + 10) % 255;
  rect(brickX, brickY, brickW, brickH);

  // draw the ball
  fill(255, 0, 0);
  ellipse(ballX, ballY, ballD, ballD);

  if (keyCode == 37) { // left cursor key
    batX -= 10;

    // keep it on the screen
    if (batX < 0) {
      batX = 0;
    }
  }

  if (keyCode == 39) {
    batX += 10;
    if (batX > (width - batW)) {
      batX = width - batW;
    }
  }
}

// when they let go of the key, reset the keyCode
void keyReleased() {
  keyCode = -1;
}

// this function checks if the ball has hit the top or sides of the bat and
// updates its direction as appropriate so the ball bouncs off the bat
void checkBallAgainstBat() {
  if (ballY + ballD > height - batH) {
    ballDy *= -1;
  }
}

// this function checks if the ball has hit the brick. It should bounce off
// the brick and return true if so
boolean checkBallAgainstBrick() {
  return false;
}

// this function checks if the ball has hit the top, left or right
// walls and update its
// direction as appropriate so the ball bounces off the walls
void checkBallAgainstWalls() {
  if (ballX + ballD > width) {
    ballDx *= -1;
  }
  if (ballX - ballD < 0) {
    ballDx *= -1;
  }
  if (ballY - ballD < 0) {
    ballDy *= -1;
  }
}

Answer 1

由于突破中的蝙蝠是一个固定的宽度，你的碰撞检测可以非常简单（伪代码）：

if (lower_edge(ball) > top_edge(bat)) { 
   // the ball has entered territory where it might have collided
   if ((left_edge(ball) <= right_edge(bat)) && (right_edge(ball) >= left_edge(bat))) {
      // the ball's within the horizontal bounds of the bat, so it's a "hit"
      ... calculate deflection ...
   } else {
      // oops, ball's gone past the bat and wasn't hit
      strike_out();
} else {
  // ball's still above the bat somewhere. do nothing
}

英语：如果球的下缘越过了球棒的顶部边缘，我们可能会发生碰撞。这只是检查比赛场的垂直轴。然后检查球的左边缘或右边缘是否落在球棒的水平位置。如果球的任何一方都与球棒重叠，那么你就输了。否则你就碰撞了，你就进行了碰撞检测。

处理中的突围（游戏）

1 个答案: