我想使用StringTokenizer搜索字符串,但我正在寻找的字符串中有一个分隔符--Java

时间:2012-01-11 03:25:43

标签: java stringtokenizer

我有一个名为quotes.txt的外部文件,我将向您展示该文件的一些内容:

1 Everybody's always telling me one thing and out the other.
2 I love criticism just so long as it's unqualified praise.
3 The difference between 'involvement' and 'commitment' is like an eggs-and-ham 
  breakfast: the chicken was 'involved' - the pig was 'committed'.

我用过这个:StringTokenizer str = new StringTokenizer(line, " .'");

这是搜索的代码:

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    while(str.hasMoreTokens()) {
       String next = str.nextToken();
       if(next.equalsIgnoreCase(targetWord) {
            wordFound = true;
            output = line;
            break;
       }
    }

    if(wordFound) break;
    else output = "Quote not found";
}

现在,我想在第1行和第2行中搜索字符串"Everybody's""it's",但由于撇号是分隔符之一,因此无效。如果我删除了该分隔符,那么我将无法在第3行中搜索"involvement""commitment""involved""committed"

我可以用这个问题做什么合适的代码?请帮助和谢谢。

2 个答案:

答案 0 :(得分:3)

我建议使用正则表达式(the Pattern class)而不是StringTokenizer。例如:

final Pattern targetWordPattern =
    Pattern.compile("\\b" + Pattern.quote(targetWord) + "\\b",
                    Pattern.CASE_INSENSITIVE);

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    if(targetWordPattern.matcher(line).find()) {
        wordFound = true;
        break;
    }
    else
        output = "Quote not found";
}

答案 1 :(得分:1)

按空格进行标记,然后按“字符”进行修剪。